Eugene can type 55 words per minuet. Allen can type 80 words in 2 minuets. If Eugene and Allen each type for 30 minuets, how man
y more words will Eugene type
1 answer:
Answer:
Step-by-step explanation:
55x30=1650 80/2=40 40x30=1200
1650-1200=450 Therefore Eugene has type 450 more words then Allen has
You might be interested in
12 is 60 percent of what number?
12 is 60% of 20
Well 15 divided by 2 would be 7.5.
Check the picture below.
![\textit{Sum and Difference Identities} \\\\ sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(255^o)\implies sin(135^o+120^o) \\\\\\ sin(135^o)cos(120^o)~~ + ~~cos(135^o)sin(120^o) \\\\\\ \left( \cfrac{\sqrt{2}}{2} \right)\left( -\cfrac{1}{2} \right)~~ + ~~\left( -\cfrac{\sqrt{2}}{2} \right)\left( \cfrac{\sqrt{3}}{2} \right)\implies -\cfrac{\sqrt{2}}{4}~~ - ~~\cfrac{\sqrt{6}}{4}\implies \cfrac{-2-\sqrt{6}}{4}](https://tex.z-dn.net/?f=%5Ctextit%7BSum%20and%20Difference%20Identities%7D%20%5C%5C%5C%5C%20sin%28%5Calpha%20%2B%20%5Cbeta%29%3Dsin%28%5Calpha%29cos%28%5Cbeta%29%20%2B%20cos%28%5Calpha%29sin%28%5Cbeta%29%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20sin%28255%5Eo%29%5Cimplies%20sin%28135%5Eo%2B120%5Eo%29%20%5C%5C%5C%5C%5C%5C%20sin%28135%5Eo%29cos%28120%5Eo%29~~%20%2B%20~~cos%28135%5Eo%29sin%28120%5Eo%29%20%5C%5C%5C%5C%5C%5C%20%5Cleft%28%20%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%5Cright%29%5Cleft%28%20-%5Ccfrac%7B1%7D%7B2%7D%20%5Cright%29~~%20%2B%20~~%5Cleft%28%20-%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%5Cright%29%5Cleft%28%20%5Ccfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%20%5Cright%29%5Cimplies%20-%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B4%7D~~%20-%20~~%5Ccfrac%7B%5Csqrt%7B6%7D%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B-2-%5Csqrt%7B6%7D%7D%7B4%7D)
x=7 because if you replace x with 7 then 4 times 7 is 28 and 28 minus 6 is 22
Answer:
it's option D.
Step-by-step explanation:
see attachment in case u need steps
