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solmaris [256]
2 years ago
15

I dont understand plz help plz i am timed i have 8 mins left plz help me

Mathematics
1 answer:
KiRa [710]2 years ago
7 0

Answer: the answer is a

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PLZZZ HURRY!
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B

Step-by-step explanation:

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7x-9x=-36<br> (I know the answer but I’m not sure if I have the work right)
pav-90 [236]

Answer:

18, is your answer!

Step-by-step explanation:

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What is the degree of polynomial?<br>With example!​
Inessa [10]

Answer:

\boxed{\mathfrak{Question ~}}

What is the degree of polynomial?

\large\boxed{\mathfrak{Answer}}

The degree of a polynomial is the highest of the degrees of the polynomial's monomials with non-zero coefficients.

Example:

{6x}^{4}  +  {2x}^{3}  + 3

4x The Degree is 1 (a variable without an

exponent actually has an exponent of 1)

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4x^ − x + 3 The Degree is 3 (largest exponent of x)

x^2 + 2x^5 − x The Degree is 5 (largest exponent of x)

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A constant polynomials (P(x) = c) has no variables. Since there is no exponent to a variable, therefore the degree is 0.

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Hãy nêu định lý pytago
Natasha_Volkova [10]

The text of the Pythagorean Theorem The Pythagorean Theorem states: “The sum of the squares of the lengths of the two sides of the right triangle, which are the shortest sides in a right-angled triangle, is equal to the square of the length of the hypotenuse, which is the longest side of the triangle.”

And in symbols: Pythagorean theorem = ( A² + B² = C²)

where ;

● A, B: the two sides of a right triangle ABC.

● C: The hypotenuse of a right triangle is ABC, which is the longest side.

It should be noted that the inverse of the theory is also true; Since the triangle to which the Pythagorean theorem applies, namely: A² + B² = C², is necessarily a right-angled triangle.

<h3><u>In Vietnamese ( Bằng tiếng việt) ;</u></h3>

Nội dung của Định lý Pitago Định lý Pitago phát biểu: “Tổng bình phương độ dài hai cạnh của tam giác vuông, là cạnh ngắn nhất của tam giác vuông, bằng bình phương độ dài của cạnh huyền, là cạnh dài nhất của tam giác. "

Và trong các ký hiệu: Định lý Pitago = (A² + B² = C²)

ở đâu ;

● A, B: hai cạnh của tam giác vuông ABC.

● C: Cạnh huyền của tam giác vuông ABC là cạnh dài nhất.

Cần lưu ý rằng điều ngược lại của lý thuyết cũng đúng; Vì tam giác áp dụng định lý Pitago, cụ thể là: A² + B² = C², nhất thiết phải là tam giác vuông.

I hope I helped you^_^

6 0
2 years ago
Prove that the diagonals of a parallelogram bisect each other​
Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof :\begin{array}{ |c| c |  c |  } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In  \: \triangle ^{s}  \:AOB \: and \: COD  } \\  \sf{(i)}&  \sf{ \angle \: OAB =  \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\  \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\  \sf{(iii)} &\sf{ \angle \: OBA=  \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\  \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}.          Proved ✔

♕ And we're done! Hurrayyy! ;)

# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P

☄ Hope I helped! ♡

☃ Let me know if you have any questions! ♪

\underbrace{ \overbrace  {\mathfrak{Carry \: On \: Learning}}} ☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

5 0
3 years ago
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