Answer:
The other zeros are -2 and 3.
Step-by-step explanation:
As 1 is a zero then (x - 1) is a factor so we divide:
x - 1 )x^3-2x^2-5x+6(x^2-x-6
x^3-x^2
-x^2-5x
-x^2+x
-6x+6
-6x+6
...........
x^2 - x - 6 = 0
(x - 3)(x + 2)
x = -2, 3.
8+(9t+4)
remove ( )
since there's a + in front of the ( ) the value will not change
8+9t+4
combine like terms
9t+12
Hope this helps
Answer: True
Step-by-step explanation:
