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3 years ago

30 points and Brainliest!

Mathematics

1 answer:

yuradex [85]3 years ago

5 0

Answer:

LF = PF given

ΔLFP is isosceles definition of isosceles triangle

∠FLP = ∠FPL isosceles triangle theorem: if two sides of a triangle are

congruent, then angles opposite those sides are

congruent.

LP = PL reflexive property

∠PDL = ∠LKP Perpendicular lines postulate (perpendicular lines form 90

degree angles)

ΔPDL ≅ ΔLKP AAS

LK = PD corresponding parts of congruent triangles are congruent

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The diagram below gives the dimensions of a swimming pool. 18 ft , 20ft, 36ft (c) What is the total area of the swimming pool? E

WARRIOR [948]

The picture in the attached figure

Part 1) What is the total area of the swimming pool?

we know that
area of the swimming pool=area rectangle-area semi circle

area rectangle=20*36-----> 720 ft²

area semicircle=pi*r²/2
r=18/2----> 9 ft
area semicircle=pi*9²/2----> 127.17 ft²

area of the swimming pool=720 ft²-127.17 ft²----> 592.83 ft²

the answer Part 1) is
The area of the swimming pool is 592.83 ft²

Part 2) What is the perimeter of the swimming pool?

perimeter of the swimming pool=perimeter of rectangle-18 ft+perimeter semi circle
perimeter of rectangle=2*[20+36]---> 112 ft

perimeter semi circle=2*pi*r/2----> pi*r
r=9 ft
perimeter semi circle=pi*9----> 28.26 ft
so
perimeter of the swimming pool=112 ft-18 ft+28.26 ft----> 122.26 ft

the answer Part 2) is
122.26 ft

6 0

3 years ago

What Is the area of the shaded part???

Aloiza [94]

Answer: The area of the shaded region is 27.74 centimeters squared

Step-by-step explanation: The diagram shows a two-in-one figure, a circle inscribed in a rectangle. The shaded region is the part of the rectangle not covered by the circle, hence we would have to subtract the area of the circle from that of the rectangle.

Area of Rectangle = L x W

Area of rectangle = 8 x 7

Area of rectangle = 56

Also,

Area of circle = Pi x r^2

Area of circle = 3.14 x 3^2

Area of circle = 3.14 x 9

Area of circle = 28.26

Area of shaded region is given as area of rectangle minus area of circle

Therefore, shaded region = 56 - 28.26

Area of shaded region = 27.74 centimeters squared

3 0

3 years ago

Find a particular solution to the nonhomogeneous differential equation y'' + 4 y = cos(2x) + sin(2x).

alukav5142 [94]

The characteristic solution follows from solving the characteristic equation,

$r^2+4=0\implies r=\pm2i$

so that

$y_c=C_1\cos2x+C_2\sin2x$

A guess for the particular solution may be $a\cos2x+b\sin2x$ , but this is already contained within the characteristic solution. We require a set of linearly independent solutions, so we can look to

$y_p=ax\cos2x+bx\sin2x$

which has second derivative

${y_p}''=(-4ax+4b)\cos2x+(-4bx-4a)\sin2x$

Substituting into the ODE, you have

$y''+4y=\cos2x+\sin2x$
$\implies4b\cos2x-4a\sin2x=\cos2x+\sin2x$
$\implies\begin{cases}4b=1\\-4a=1\end{cases}\implies a=-\dfrac14,b=\dfrac14$

Therefore the particular solution is

$y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x$

Note that you could have made a more precise guess of

$y_p=(a_1x+a_0)\cos2x+(b_1x+b_0)\sin2x$

but, of course, any solution of the form $a_0\cos2x+b_0\sin2x$ is already accounted for within $y_c$ .