Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
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* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.
As time time starts at zero, he is at home. As time goes on, he travels to a given location, which is why his distance increases. He then stays there for a while which is why the time continues to go on but his distance doesn't change. He then rides home quickly.
★ QUADRATIC RESOLUTION ★
Roots of the given equation will be imaginary because it's discriminant is less than 0 and hence it'll yield imaginary solutions
D < 0
b² - 4ac < 0
4² - 4 ( 5 ) < 0
16 - 20 < 0
-4 < 0
Hence it's character is stated above
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Answer:
(4)
Step-by-step explanation:
As the circumference of a circle measures 360 degrees, minor arc AC measures 360-268=92 degrees.
By the inscribed angle theorem, angle ABC measures 46 degrees.
