What value of s makes the equation true?

Mathematics

2 answers:

scoundrel [369]3 years ago

6 0

Answer:

s = -17

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

-8s + 4 = -7s + 21

Step 2: Solve for s

[Addition Property of Equality] Add 7s on both sides: -s + 4 = 21
[Subtraction Property of Equality] Subtract 4 on both sides: -s = 17
[Division Property of Equality] Divide -1 on both sides: s = -17

azamat3 years ago

5 0

Answer:

-17 =s

Step-by-step explanation:

-8s +4 = -7s +21

Add 8s to each side

-8s+8s +4 = -7s+8s +21

4 = s+21

Subtract 21 from each side

4-21 = s+21-21

-17 =s

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Identify any zeros of y=x^2+4x+5.

Jet001 [13]

A there are no real zeros

using the discriminant b² - 4ac to determine the nature of the zeros

for y = x² + 4x + 5 ( with a = 1, b = 4 and c = 5 )

• If b² - 4ac > 0 there are 2 real and distinct zeros

• If b² - 4ac = 0 there is a real and equal zero

• If b² - 4ac < 0 there are no real zeros

b² - 4ac = 16 - 20 = - 4

Since discriminant < 0 there are no real zeros

3 0

3 years ago

Find the quadratic function that has the vertex (4,5) and passes through the point (8,21) If possible, can you explain the work?

Ganezh [65]

Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!