Luis and Sara both open savings accounts at the same bank. Luis opens his account with $125 and deposits $60 per week. Sara open
2 answers:
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Answers:
(a) f is increasing at
.
(b) f is decreasing at
.
(c) f is concave up at
(d) f is concave down at
Explanations:
(a) f is increasing when the derivative is positive. So, we find values of x such that the derivative is positive. Note that
So,
The zeroes of (x - 2)(x + 2) are 2 and -2. So we can obtain sign of (x - 2)(x + 2) by considering the following possible values of x:
-->> x < -2
-->> -2 < x < 2
--->> x > 2
If x < -2, then (x - 2) and (x + 2) are both negative. Thus, (x - 2)(x + 2) > 0.
If -2 < x < 2, then x + 2 is positive but x - 2 is negative. So, (x - 2)(x + 2) < 0.
If x > 2, then (x - 2) and (x + 2) are both positive. Thus, (x - 2)(x + 2) > 0.
So, (x - 2)(x + 2) is positive when x < -2 or x > 2. Since
Thus, f'(x) > 0 only when x < -2 or x > 2. Hence f is increasing at.
(b) f is decreasing only when the derivative of f is negative. Since
Using the similar computation in (a),
Based on the computation in (a), (x - 2)(x + 2) < 0 only when -2 < x < 2.
Thus, f'(x) < 0 if and only if -2 < x < 2. Hence f is decreasing at (-2, 2)
(c) f is concave up if and only if the second derivative of f is positive. Note that
Since,
Therefore, f is concave up at.
(d) Note that f is concave down if and only if the second derivative of f is negative. Since,
Using the similar computation in (c),
Therefore, f is concave down at.
(a) f is increasing at
(b) f is decreasing at
(c) f is concave up at
(d) f is concave down at
Explanations:
(a) f is increasing when the derivative is positive. So, we find values of x such that the derivative is positive. Note that
So,
The zeroes of (x - 2)(x + 2) are 2 and -2. So we can obtain sign of (x - 2)(x + 2) by considering the following possible values of x:
-->> x < -2
-->> -2 < x < 2
--->> x > 2
If x < -2, then (x - 2) and (x + 2) are both negative. Thus, (x - 2)(x + 2) > 0.
If -2 < x < 2, then x + 2 is positive but x - 2 is negative. So, (x - 2)(x + 2) < 0.
If x > 2, then (x - 2) and (x + 2) are both positive. Thus, (x - 2)(x + 2) > 0.
So, (x - 2)(x + 2) is positive when x < -2 or x > 2. Since
Thus, f'(x) > 0 only when x < -2 or x > 2. Hence f is increasing at
(b) f is decreasing only when the derivative of f is negative. Since
Using the similar computation in (a),
Based on the computation in (a), (x - 2)(x + 2) < 0 only when -2 < x < 2.
Thus, f'(x) < 0 if and only if -2 < x < 2. Hence f is decreasing at (-2, 2)
(c) f is concave up if and only if the second derivative of f is positive. Note that
Since,
Therefore, f is concave up at
(d) Note that f is concave down if and only if the second derivative of f is negative. Since,
Using the similar computation in (c),
Therefore, f is concave down at
The translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.
In the question, we are asked to translate the given figure 2 units left and 7 units down.
In the translation, the left-right movement implies the change in the x-coordinate, whereas the up-down movement implies the change in the y-coordinate.
For any point P(x, y) the given rule says that after translation,
P(x, y) becomes P'(x - 2, y - 7).
The coordinates of the given figure are:
A(3,9), B(5,9), C(5,2), and D(1,4).
After translation, these points can be shown as:
A(3,9) becomes A'(1,2).
B(5,9) becomes B'(3,2).
C(5,2) becomes C'(3,-5).
D(1,4) becomes D'(-1,-3).
Thus, the translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.
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Total distance the rover need to travel is .
<u>Step-by-step explanation:</u>
We have , Garne Problem med . A rover needs to travel mile to reach its destination traveled mile. a rover needs to travel 5/8 mile to reach its destination it has already travel 3/8 miles . We need to find that how much farther does the rover need to travel , Let's do it step by step:
First , rover has already traveled 3/8 miles , Let total distance to be traveled by rover is D :
⇒ , where d is distance left to cover .
Now, rover need to travel 5/8 miles more to reach destination :
⇒ , where d is distance left to cover , So
⇒
⇒
⇒
⇒
⇒
∴ Total distance the rover need to travel is .