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katovenus [111]
2 years ago
7

A bicycle tire has a radius of 26 inches. How many revolutions will this tire make if the bicycle is pedaled 1 mile? (Use 3.14 f

or π and 1 mile = 5280 feet).
Mathematics
1 answer:
Fittoniya [83]2 years ago
4 0
How far does a wheel move when it rotates once? The length of the outside of the tyre? Isn't that the same as the circumference?
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Tristan records the number of customers who visit the store each hour on a Saturday. His data representing the first seven hours
Alona [7]

Answer:

Option C is correct.

Step-by-step explanation:

We have been given total 8 data

Data is : 12,15,18,20,23,23,28

Here, n=7

Median is \frac{n+1}{2}=\frac{7+1}{2}=4th term

Median is 20.

When one data is added n=8

The median of  even number of data is  

median=\frac{\frac{n}{2}\text{th and}\frac{n}{2}+1\text{th}}{2}

Median is \frac{8}{2}\text{th and}\frac{8}{2}+1th

Median is 4\text{th and}5th

4th terms is 20

5th terms is 23

Since, median should not be change hence,

Median will be 20.

Therefore, option C is correct.

6 0
3 years ago
Read 2 more answers
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
17x2 - 5x + 10x - 8x2
USPshnik [31]

Answer:

9x2+5x

Step-by-step explanation:

combine like terms

4 0
3 years ago
Please help<br> do step by step<br> I learn diff
Lesechka [4]
1.5 use a calculator
6 0
2 years ago
Read 2 more answers
A country's population in 1991 was 147 million. In 1998 it was 153 million. Estimate the population in 2017 using the exponentia
Aloiza [94]
K = ln (153/147)/7
k = <span> ln (<span> <span> 1.0408163265)/7
k = </span></span></span>0.040005334584

y(t) = a * e ^ k*t

y(2017) = 147 * e^ <span><span><span>0.040005334584 </span> </span> </span> * 26
y(2017) = 147*e^ <span> <span> <span> 1.0401386992 </span> </span> </span>
y(2017) = 147* <span> <span> <span> 2.8296094512 </span> </span> </span>
<span>y(2017) = 415.95 NOT very sure of that answer


</span>









6 0
3 years ago
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