Answer:
75?
Step-by-step explanation:
1/4 = 25
25 x 3 =75
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3/4=75
Answer:
The height of the tower is 130.5m
Step-by-step explanation:
In the question, we are given the following values:
The angles of elevation to the top of the tower from P = 50°
The angles of elevation to the top of the tower from Q = 45°
The angles of elevation to the top of the tower from P = 50°
Hence,cot P = 1/ tan(50°)
The angles of elevation to the top of the tower from Q = 45°
Hence, tan 45° = 1
In the question,we are told Points P and Q lie 240 m apart in line with and on opposite sides of a communications tower.
Therefore,
PQ = height of the tower( tan Q + 1/tan P)
240m = height of the tower( tan 45° + 1/ tan 50°)
240m = h(1 + 1/tan 50°)
h = (240 m)/(1 + 1/tan (50°))
h = 130.49863962 meters
Therefore, the height of the tower to the nearest tenth of a meter is 130.5 meters(m)
Answer: HOPE THIS HELPED! :D
5 x 15 = 75
Step-by-step explanation:
15 is 3x 5
and product do 3x15 is 75
so answer would be
5 & 15
Answer:
1cm=5ft
Step-by-step explanation:
divide 15 by three
A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:
n!/((n-r)!r!)
In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.
5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5
5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10
5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10
5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5
Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.
Now we add together the combinations
1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.
The answer is 32.
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Note: There is also an equation for permutations which is:
n!/(n-r)!
Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.
We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.
I hope this helps! If you have any questions, let me know :)
