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BabaBlast [244]
3 years ago
10

I really need the answer for this

Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer:

qwwertyuiop

Step-by-step explanation:

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Please help! Thank you!
makvit [3.9K]
It would be 2,400 i’m pretty certain
4 0
2 years ago
A contractor combined x tons of a gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that co
White raven [17]

Answer:

The value of x would be \frac{3}{5}y or \frac{3}{8}z

Step-by-step explanation:

Given,

x tons of 10% gravel G mixture is mixed with y ton of 2% gravel G to obtain  5% gravel mixture,

Thus, gravel G in x ton + gravel in y ton = gravel G in the resultant mixture,          

⇒ 0.1x + 0.02y = 0.05(x+y),

0.1x - 0.05x = 0.05y - 0.02y

0.05x = 0.03y

\implies x = \frac{0.03}{0.05}y=\frac{3}{5}y----(1)

Now, resultant mixture is z ton,

i.e. z=x+y

\implies y = z - x

From equation (1),

x=\frac{3}{5}(z-x) = \frac{3}{5}z-\frac{3}{5}x

x+\frac{3}{5}x=\frac{3}{5}z

\frac{8}{5}x=\frac{3}{5}z

x=\frac{3}{8}z

3 0
3 years ago
The answer to this problem?
LenaWriter [7]

The simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

<h3>How to simplify the expression?</h3>

The expression is given as:

\sqrt{\frac{162x^9}{2x^{27}}}

Divide 162 and 2 by 2

\sqrt{\frac{81x^9}{x^{27}}}

Take the square root of 81

9\sqrt{\frac{x^9}{x^{27}}}

Apply the quotient rule of indices

9\sqrt{\frac{1}{x^{27-9}}}

Evaluate the difference

9\sqrt{\frac{1}{x^{18}}}

Take the square root of x^18

\frac{9}{x^9}

Hence, the simplified expression of \sqrt{\frac{162x^9}{2x^{27}}} is \frac{9}{x^9}

Read more about expressions at:

brainly.com/question/723406

#SPJ1

5 0
1 year ago
Geoff earns $9.25 per hour before taxes, and he works 40 hours per week. Geoff's employer withholds (takes out) 10.65% of geoff'
Snowcat [4.5K]

Answer:

a

Step-by-step explanation:

6 0
2 years ago
Graph the parabola 3x^2+6x-24
brilliants [131]
We have the following function:
 F (x) = 3x ^ 2 + 6x-24
 We observe that it is a quadratic equation.
 The graph is therefore a parabola.
 Its cut points are:
 (-4, 0)
 (2, 0)
 Answer:
 
See attached image to see graph of the function

7 0
3 years ago
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