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BabaBlast [244]
3 years ago
10

I really need the answer for this

Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer:

qwwertyuiop

Step-by-step explanation:

You might be interested in
What is /-7/ - /3/ ?
Olenka [21]

Answer:

4

Step-by-step explanation:

the absolute value of -7 is seven and the absolute value of 3 is 3.

7-3=4

4 0
3 years ago
you should have $16 and a coupon for a $5 discount at a local supermarket. a bottle of olive oil costs$7. how many bottles of ol
natta225 [31]
Each bottle costs seven dollars. Two of them would cost $14 and three would cost $21. Buying three bottles, the amount is $21 which exceeds $16. Therefore, a $5 discount will be given. Subtracting $5 from the $21 will give $16. You have just enough amount to buy THREE bottles of olive oil. 
4 0
3 years ago
The head of the Westlane Cultural Center wants to get a sense of how quickly pledges from donors arrive at the center. It takes
Rzqust [24]

Answer:

95.64% probability that pledges are received within 40 days

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 28, \sigma = 7

What is the probability that pledges are received within 40 days

This is the pvalue of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 28}{7}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564

95.64% probability that pledges are received within 40 days

7 0
3 years ago
Question 8 (06.02 LC)
kodGreya [7K]
Question 8.
The best answer would be A, two times y divided by 7.

Question 9.
The distributive property. Or A.

Question 10.
5(2+y) would be the answer. So, D.

Hope this helps!


8 0
3 years ago
The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,
uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right).

We need to solve it and obtain an expression for P(t) in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right).

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that k=0.04 and K=500 and the initial condition P(0)=100.

Notice that this equation is separable, then

\frac{dP}{P(1-P/K)} = kdt.

Now, intagrating in both sides of the equation

\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C.

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}.

So,

\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|.

We have obtained that:

-\ln\left| \frac{K-P}{P}\right| = kt +C

which is equivalent to

\ln\left| \frac{K-P}{P}\right|= -kt -C

Taking exponentials in both hands:

\left| \frac{K-P}{P}\right| = e^{-kt -C}

Hence,

\frac{K-P(t)}{P(t)} = Ae^{-kt}.

The next step is to substitute the given values in the statement of the problem:

\frac{500-P(t)}{P(t)} = Ae^{-0.04t}.

We calculate the value of A using the initial condition P(0)=100, substituting t=0:

\frac{500-100}{100} = A} and A=4.

So,

\frac{500-P(t)}{P(t)} = 4e^{-0.04t}.

Finally, as we want the value of t such that P(t)=200, we substitute this last value into the above equation. Thus,

\frac{500-200}{200} = 4e^{-0.04t}.

This is equivalent to \frac{3}{8} = e^{-0.04t}. Taking logarithms we get \ln\frac{3}{8} = -0.04t. Then,

t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325.

So, the population of rats will be 200 after 25 months.

6 0
3 years ago
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