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3 years ago

Solve using the substitution method. What is the y coordinate of the solution?

Mathematics

1 answer:

Slav-nsk [51]3 years ago

3 0

If this is solve using system of equations it would be 2,0 for substitution

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mridul jogs around a rectangular park of 100m by 80m at the rate of 9km per hour. how much time will he take in jogging 6 rounds

anyanavicka [17]

Answer:

14minutes

Step-by-step explanation:

first you need to find the distance which you must find the perimeter P=100+80+100+80

=360 so you multiple it by 6 to get

=2160meters

so you need to convert the meters to kilometers

which is 1000m =1km

what about 2160m you cross multiply

to get 2.16km.

so the distance represent D=2.16 km

and speed represent S=9km

now you need to find time represented by T

T=D/S

T=2.16km/9km/h

so the km cancels each other

you get 0.24h for this isn't the solution

you know that 1 hour= 60 minutes

 what about 0.24h you cross multiply

to get 14.4 so you round it off to get 14 minutes

3 0

3 years ago

HELP PlS ASAP

Anarel [89]

Answer:

The correct answer is option B.

Step-by-step explanation:

Two point form of the equation:

A line passing through the point (-1,6) with slope ,m = -3.

The equation of the line will be: y-6= (-3)(x-(1))=(-3)(+1)

3 0

2 years ago

If ΔPQR ≅ ΔJKL and ∠P = 35º, then which other angle also equals 35º. a ∠J b ∠K c ∠L d None of these choices are correct.

aivan3 [116]

Answer:

A: Angle J

Step-by-step explanation

If the two triangles are congruent then their corresponding angles are also congruent. This means that angle P is congruent to angle J, angle Q is congruent to angle K and angle R is congruent to angle L. Hope this helps :D

3 0

2 years ago

Find the greatest comman factor of 15 and 20

Darina [25.2K]

The greatest common factor of 15 and 20 is 5

4 0

3 years ago

Read 2 more answers

What is the answer to this problem 0.05n+0.10(2n)=9.25

kolbaska11 [484]

Answer: n=37

Step-by-step explanation:

0.05n+0.10x2n=9.25

0.25n=9.25

n=9.25/0.25

n=37

6 0

2 years ago