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scZoUnD [109]
3 years ago
8

The measures of the base angles of an isosceles triangle are 3x 5 and 5x - 25. The measure of the vertex angle is 6x - 10. Find

the measure of the vertex angle.
Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer: The measure of the vertex angle = 80°

Step-by-step explanation:

Angle sum property of triangle : The sum of the measures of the angles for any triangle is 180 degrees.

So,

3x+ 5 + 5x-25+6x-10= 180\\\\\Rightarrow\ 14x-30=180\\\\\Rightarrow\ 14x= 210\\\\\Rightarrow x=\dfrac{210}{14}=15'

Then, vertex angle = 6(15)-10=90-10= 80

Hence, The measure of the vertex angle = 80°

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A parallelogram has sides 10m and 12m and an angle of 45°. Find the distance between the 12m-sides.
stich3 [128]

Answer:

The distance between 12m-sides is 5\sqrt{2}m.

Step-by-step explanation:

It is given that the parallelogram has sides 10m and 12m and an angle of 45°.

Draw an altitude from one 12m side to another 12 m side as shown in below figure.

The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.

Since angle C is acute angle therefore it must be 45 degree.

\sin\theta=\frac{perpendicular}{hypotenuse}

\sin C=\frac{BE}{BC}

\sin(45^{\circ})=\frac{d}{10}

\frac{1}{\sqrt{2}}=\frac{d}{10}

\frac{10}{\sqrt{2}}=d

\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=d

\frac{10\sqrt{2}}{2}=d

5\sqrt{2}=d

Therefore the distance between 12m-sides is 5\sqrt{2}m.

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max2010maxim [7]

Answer:

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Step-by-step explanation:

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7 0
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I hope this helps :)

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