The second attachment I solved in your another question.You may refer to that.
#1
Apply Pythagorean theorem
x²=10²-6²
Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:


h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.
The hypotenuse is the square root of 58.
a^2+b^2=c^2
7^2+3^2=c^2
49+9=c^2
58=c^2
c= square root of 58
56 dived by 2 equals 28. 28=green ribbon. Brown ribbon is 4 times as long. 28 times 4 equals 112. The brown ribbon is 112 cm long.
Rational numbers end
irrational numbers do not
pi is an irrational number
√2 is an irrational number
so
√50=√2 times √25=√2 times 5
irrational times rational =irrational
√2=irrational
answer is false, it is rrational