Answer:
Let R = radius of big circle
r=radius of small circle
A1=Area of small circle
A2=Area of big circle
R=9r
A1=50cm^2
A1=pi*r*2
A2=pi*R^2
A2=pi*(9r)^2
A2=81*pi*r^2
A2=81*A1
A2=4050cm^2
Hence the big circle has area of 4050cm^2
Step-by-step explanation:
2nd subtraction property.
Answer:
141
Step-by-step explanation:
141
Answer:
Step-by-step explanation:1/2 of answer is zero