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KATRIN_1 [288]
3 years ago
12

. Find the domain and range of y=(3-x)2-8.​

Mathematics
1 answer:
HACTEHA [7]3 years ago
3 0

Domain : ( – ∞ ,  ∞ ) , {x/x ∈ R }

Range : [ 0 ,  ∞ ) , { y/y ⩾ 0 }

I hope I helped you^_^

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Does the graph represent a function? Why or why not? ​
Shalnov [3]

Answer:

The vertical line test can be used to determine whether a graph represents a function. ... If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because that x value has more than one output. A function has only one output value for each input value.

Step-by-step explanation:

Can i get braineist pls

3 0
3 years ago
Find the solutions to x2 = 20.
Gemiola [76]

Answer:

B.

Step-by-step explanation:

x^2=20; \ => \ \left[\begin{array}{ccc}x=\sqrt{20} \\x=-\sqrt{20} \end{array} \ => \ \left[\begin{array}{ccc}x=2\sqrt{5} \\x=-2 \sqrt{5} \end{array}

3 0
3 years ago
Mrs. Trout estimated her math class next year would include 28 students. The actual size of the class turned out to be 32 studen
Alja [10]
The answer she has is not correct.
 All the steps she did are correct, except they forgot to convert the decimal answer into the proper percentage by multiplying it by 100.

The correct answer should be 0.125 * 100 = 12.5%
7 0
3 years ago
Read 2 more answers
Andrew is about to leave for school. If he walks at a speed of 50 meters per minute, he will arrive 3 minutes after the bell rin
Mariana [72]

Answer:

The answer is: 13 minutes

Step-by-step explanation:

First Let us form equations with the statements in the two scenario

time=\frac{distance}{speed}

Let the time in which the bell rings be 'x'

1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes

3 + x =\frac{distance}{50}\\distance = 50(3+x) - - - - - (1)

2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes

x - 3 = \frac{distance}{80} \\distance = 80(x-3)   - - - - - (2)

In both cases, the same distance is travelled, therefore, equation (1) = equation (2)

50(3+x)=80(x-3)

150 +50x=80x-240\\

Next, collecting like terms:

150 + 240 = 80x - 50x\\390 = 30x\\30x = 390\\

dividing both sides by 3:

x =  390÷30 = 13

∴ x = 13 minutes

7 0
3 years ago
When A is divided by the sum of a certain number and 10, the result is the same as dividing 3 by the sum of that number and 4 .
tensa zangetsu [6.8K]

When A is divided: A /

By the sum of a certain number and 10: (n + 10)

When A is divided by the sum of a certain number and 10: A / (n + 10)

The result is the same as: =

Dividing 3: 3 /

By the sum of that number and 4: (n + 4)

The result is the same as dividing 3 by the sum of that number and 4: 3 / (n + 4).

Final Equation: A / (n + 10) = 3 / (n + 4)

To solve, we'll need to cross-multiply. Without knowing the value of A, however, the answer will not be a numerical value.

3(n + 10) = A(n + 4)

3n + 30 = An + 4A

30 - 4A = An - 3n

30 - 4A = n(A - 3)

n = (30 - 4A) / (A - 3)

If you know the value of A, then please plug it in to the value for n given above.

Hope this helps!

5 0
2 years ago
Read 2 more answers
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