Question

Sally found that a solution of x = 2 was extraneous for her function. What would be a possible denominator in Sally's function? 4x + 8; 2x + 12; x^2 - 4; x^2 - 16

Answer 1

$x^2-4$ because for $x=2$ it would be equal 0.<span />

Answer 2

Answer:

$4x+8\text{and}x^2-4$

Step-by-step explanation:

Extraneous is the point where the solution of a function exists and it gives the value  of denominator  zero

In case of $f(x)=4x+8=0$

can be the denominator in sally's function.

In case of $f(x)=2(-2)+12=8$ not the possible denominator because we are not getting zero at this point.

In case of $f(x)=(-2)^2-4=0$ is the possible denominator

in case of $f(x)=x^2-16=(-2)^2-16=-12$ is the not the possible denominator.