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Mazyrski [523]
3 years ago
9

Solve this system of equations: y = 7; y = -2x+1 *

Mathematics
2 answers:
k0ka [10]3 years ago
8 0

Answer:

x = -3

Step-by-step explanation:

y = 7

y = -2x+1

substitute for y

7 = -2x+1

subtract 1 from each side

6 = -2x

divide both sides by -2

6/-2 = x

x = -3

Gnoma [55]3 years ago
6 0

Answer:

x = -3

y = 7

Step-by-step explanation:

y = -2x + 1

7 = -2x + 1

<u>-1           -1 </u>

6 = -2x

divide by -2

x = -3

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Answer: \bold{(x-2)^2+(y-3)^2=\dfrac{1}{4}}

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<u>Step-by-step explanation:</u>

When both the x² and y² values are equal and positive, the shape is a circle. Complete the square to put the equation in format:

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1) Group the x's and y's together and move the number to the right side

   4x² - 16x         + 4y² - 24y               = -51        

2) Factor out the 4 from the x² and y²

    4(x² - 4x          ) + 4(y² - 6y            ) = -51

3) Complete the square (divide the x and y value by 2 and square it)

    4[x^2-4x+\bigg(\dfrac{-4}{2}\bigg)^2]+4[y^2-6y+\bigg(\dfrac{-6}{2}\bigg)^2]=-51+4\bigg(\dfrac{-4}{2}\bigg)^2+4\bigg(\dfrac{-6}{2}\bigg)^2

  = 4(x - 2)² + 4(y - 3)² = -51 + 4(-2)² + 4(-3)²

  = 4(x - 2)² + 4(y - 3)² = -51 + 4(4) + 4(9)

  = 4(x - 2)² + 4(y - 3)² = -51 +  16  +  36

  = 4(x - 2)² + 4(y - 3)² = 1

4) Divide both sides by 4

   (x-2)^2+(y-3)^2=\dfrac{1}{4}

  • (h, k) = (2, 3)
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