m∠5 = x + 1
m∠5 = 60°
Solution:
Given data:
Line a and Line b are parallel lines.
The line that crosses both a and b is a transversal line.
m∠1 = x + 1 and m∠6 = 2x + 2.
<em>If two parallel lines cut by a transversal, then their corresponding angles on the same side are congruent.</em>
∠5 and ∠1 are corresponding angles.
⇒ m∠5 = m∠1
⇒ m∠5 = x + 1
Now, ∠5 and ∠6 forms a linear pair.
m∠5 + m∠6 = 180°
x + 1 + 2x + 2 = 180°
3x + 3 = 180°
Subtract 3 from both sides.
3x = 177°
Divide by 3 on both sides.
x = 59°
m∠5 = 59° + 1° = 60°
m∠5 = 60°
Answer:
H
Step-by-step explanation:
3:2 IS EQUAL TO 3/2
Answer:
y = -8x + 54
Step-by-step explanation:
Since the lines are parallel, their slopes are the same, leaving you with y = -8x.
That equation at x = 7 would make y -56, but we want it to be -2. Therefore we add a 54 in the end, leaving you with y = -8x + 54.
I hope this helped.
Answer:
0.247
Step-by-step explanation: