We have a line y = 1/3x -6
We want a line that is perpendicular to this line
Perpendicular lines have slopes that multiply to -1
1/3 * m = -1
3 * 1/3 *m = -1 * 3
m = -3
The slope of the perpendicular line is -3
y = mx+b where m is the slope and b is the y intercept
y = -3x+b
We have a point on the line ( 7 ,-23)
Substitute this point into the equation
-23 = -3(7)+b
-23 = -21+b
Add 21 to each side
-23+21 = -21+21+b
-2 = b
y = -3x-2
In slope intercept form, the line perpendicular passing through (7,-23) is
y = -3x-2
Answer:
1.1352 L
Step-by-step explanation:
L = qt 1.0567
qt = 0.946 L
1:4 = 5
0.946/5 = 0.1892 L one part
0.1892 x 11 = 2.0812 11 parts as 1+10 =11
Answer therefore is subtracting 5 from 11 parts to get the final 6 parts added = 2.0812 - 0.946
= 1.1352 L
D= 65 degrees.
Because straight line adds up to 180
So 180-115= 65
Answer:
FINE ITS A AND B
Step-by-step explanation:
