Write yhr equation in standard form of the line with m=3/4 and b=6

A coin is tossed 600times with the frequencies as:

brilliants [131]

Answer:

see below

Step-by-step explanation:

Total number of trials =600.

Number of heads = 342.

Number of tails = 258

On tossing a coin,

$let \: E_1 \: and \: E_2 \: be \: the \: events \: of \: getting \: a \: head$

and of getting a tail respectively.

then,

$1) \: P \: (getting \: a \: head) = \: P \: (E_1)$

$\longrightarrow \: \frac{number \: of \: heads \: coming \: up}{total \: number \: of \: trials}$

$\longrightarrow \: \frac{342}{600} = \frac{57}{100}$

$\longrightarrow \: 0.57$

$\red{ \rule{150pt}{3pt}} \:$

$2) P (getting \: a\: tail) =P (E_2)$

$\longrightarrow \: \frac{number \: of \: tails \: coming \: up}{total \: number \: of \: trials}$

$\longrightarrow \: \frac{258}{600} = \frac{43}{100}$

$\longrightarrow \: 0.43$

6 0

3 years ago

In the triangle below the value of h is 3/4 the side length labeled on the figure. What is the area of the triangle ?

Molodets [167]

I'm not sure if this is the answer, but this is how I solved it.
A= 1/2 bh (area of a triangle) (1/2 times base times height)
A=1/2 * 3/4
A=3/8?
Do have the picture of the triangle by any chance?

7 0

3 years ago

the length of a rectangle is 4 meters less than twice its width. The area of the rectangle is 70. Find the dimensions of the rec

Savatey [412]

Answer: The width is 7 meters. The length is 10 meters.

Step-by-step explanation: Area = Length × width

Length is 2w - 4

Substitute that value for length, then solve for w.

70 = w(2w - 4)

70 = 2w² - 4w reorganize to quadratic equation form

2w² - 4w -70 = 0 These are All even numbers; factor out 2 (divide all by 2)

w² - 2w - 35 = 0 factor this

(w - 7)(w + 5) set each factor = 0 and calculate the value of w.

w+5=0 w= -5 (disregard this one because dimensions of real rectangles can't be negative)

w - 7 = 0 w = 7 <u>The width is 7</u>

Substitute into the original expressions to get the value of Length.

2(7) -4 = L 14 - 4 = L The<u> Length is 10.</u>

Check by substituting into the original equation:

w × 2w -4 = 70

7 × 2(7) -4 = 70

7 × 10 = 70 TRUE!

w

6 0

3 years ago

Need help with the picture

Katen [24]

Answer:

E F D C A B

Step-by-step explanation:

thats the order the letters go in

5 0

3 years ago

Read 2 more answers

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple. How many ways are there to choose:(

Volgvan

Answer:

The number of ways of selecting of n items form r different items = $^{(n+r-1)}C_{(r-1)}$

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple.

A) How many ways are there to choose 32 candies?

So, n = no. of items = 32

r = no. of types of items = 5

So, No. of ways to choose 32 candies = $^{(32+5-1)}C_{(5-1)}$

= $^{36}C_{4}$

= $\frac{36!}{4!(36-4)!}$

= $58905$

So, No. of ways to choose 32 candies is 58905

B)32 candies with at least a piece of each flavor?

Out of 32 you choose 5 candies of different types

So, Remaining candies = 32 - 5 = 27

So, No. of ways to choose 27 candies = $^{(27+5-1)}C_{(5-1)}$

= $^{31}C_{4}$

= $\frac{31!}{4!(31-4)!}$

= $31465$

So, No. of ways to choose 32 candies with at least a piece of each flavor is 31465

C) 32 candies with at least 4 cherry and at least 6 lemon?

So, you already choose 6+4= 10

So, remaining candies = 32-10 = 22

So, No. of ways to choose 22 candies = $^{(22+5-1)}C_{(5-1)}$

= $^{26}C_{4}$

= $\frac{26!}{4!(26-4)!}$

= $14950$

Hence No. of ways to choose 32 candies with at least 4 cherry and at least 6 lemon is 14950

8 0

4 years ago