All categories

3 years ago

Is 1 greater than, less than, or equal to 8/10?

Mathematics

2 answers:

VladimirAG [237]3 years ago

7 0

Answer:

Greater than

Step-by-step explanation

1 is greater than 0.8

grandymaker [24]3 years ago

5 0

Answer:

Greater than ( > )

Step-by-step explanation:

You might be interested in

Change the following algebraic expressions to the statement in words: i. 3mn +7 ii. xy + (x+y)

kicyunya [14]

Answer:

i) 3*m*n + 7

Then we can write the first term as:

"3 times the product between two numbers"

Where the product of two numbers is m*n

And after that we need to add 7, then the complete sentence is:

"3 times the product between two numbers, increased by 7"

ii) x*y + (x + y)

The first part, x*y, can be written as:

"the product of two numbers"

where the two numbers are the number x and the number y.

After that, we add the sum of these two numbers, then the complete sentence can be:

"the product of two numbers, plus the sum of these two numbers"

8 0

3 years ago

For f(x)=4x+1 and g(x)=x^2-5 find (f-g)(x)

Marrrta [24]

$f(x)=4x+1,\ g(x)=x^2-5\\\\(f-g)(x)=f(x)-g(x)\\\\\text{Therefore}\\\\(f-g)(x)=(4x+1)-(x^2-5)=4x+1-x^2+5=-x^2+4x+6$

6 0

3 years ago

Read 2 more answers

Trigonometria del ángulo<br>3 Calcula las razones<br>agudo de mayor amplitud de la figura

RSB [31]

Answer:

lol

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago

Which is the Area of a circle with a diameter of 7 units?

saul85 [17]

Area of a circle = (3.14) * r^2
d = 7
r = 3.5

a = (3.14) * 3.5^2
a = (3.14) * 12.25
a = 38.47

7 0

3 years ago