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Neporo4naja [7]
3 years ago
8

A truck travels 500 miles at an average speed of 60 miles per hour on a return trip on the same route and travels at an average

speed of 50 miles per hour how much longer did the return trip take
Mathematics
1 answer:
marta [7]3 years ago
8 0

The return trip took 1 hour 42 minutes longer

Further explanation:

The distance will remain same on return.

The formula for speed is given by:

Speed=\frac{Distance}{Time}

Let d be the distance

s1 be the speed while going and s2 be the speed while returning

and

t1 be the time while going and t2 be the time while returning

d=500 miles

s1=60 miles per hour

s2=50 miles per hour

We have to calculate time for both trips,

So,

<u>Time while Going:</u>

<u>s_1=\frac{d}{t_1}\\t_1=\frac{d}{s_1}</u>

<u>Putting the values of d and s1</u>

<u>t_1=\frac{500}{60}\\=8.3\ hours</u>

<u>Converting 8.3</u>

8 will be the hours,

for 0.3 hour

0.3*60=18 minutes

The first trip took 8 hours and 18 minutes.

<u>Time while returning:</u>

s_2=\frac{d}{t_2}\\t_2=\frac{d}{s_2}

Putting the values of d and s1

t_2=\frac{500}{50}\\=10\ hours

The difference of both times is: 1 hour 42 minutes

So,

The return trip took 1 hour 42 minutes longer

Keywords: Time, Distance, Speed

Learn more about movement at:

  • brainly.com/question/2367554
  • brainly.com/question/2670657

#LearnwithBrainly

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