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3 years ago

Systems of equation:substitution

Mathematics

1 answer:

Igoryamba3 years ago

6 0

Step-by-step explanation:

describe y in terms of x

y=5+x

so now replace y with terms of x

5+x+3x=37

4x=32

x=8

y=13

do the same here

x=y+1

2y+x=19

2y+y+1=19

3y=18

x=6

y=7

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Answer: I cant see image!!!

Step-by-step explanation:

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3 years ago

Read 2 more answers

Solve. x2 + 14 = 9x A) x = 2, x = 7 B) x = 3, x = 5 C) x = −2, x = −7 D) x = −3, x = −5

chubhunter [2.5K]

Answer:

A) x = 2, x = 7

Step-by-step explanation:

x^2 + 14 = 9x

Subtract 9x from each side

x^2-9x + 14 = 9x-9x

x^2-9x + 14 = 0

What 2 numbers multiply to 14 and add to -9

-7*-2 = 14

-7+-2 = -9

(x-7)(x-2) = 0

Using the zero product property

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3 years ago

Write the equation of a circle for which the endpoints of a diameter are (-2,-2) and (4,-10)

Maurinko [17]

Answer:

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

Step-by-step explanation:

Given:

End point of Diameter be

point A( x₁ , y₁) ≡ ( -2 ,-2 )

point B( x₂ , y₂) ≡ ( 4 , -10 )

To Find:

Equation of a circle =?

Solution:

When end points of the Diameter are A( x₁ , y₁) , B( x₂ , y₂). then the Equation of Circle is given as

$(x-x_{1})(x-x_{2})+(y-y_{1})(y-y_{2})=0$

Substituting the end point are

$(x-(-2))(x-4)+(y-(-2))(y-(-10))=0\\(x+2))(x-4)+(y+2))(y+10))=0\\$

Applying Distributive Property we get

$x^{2} -2x-8+y^{2}+12y+20 =0\\\\x^{2}+y^{2}-2x+12y+12=0$

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

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2 years ago

Standardization of Normal Distribution is the process of

n200080 [17]

Answer:

Step-by-step explanation:

Standardizing a normal distribution is to convert a normal distribution to the standard normal distribution. In real-world applications, a continuous random variable may have a normal distribution with a value of the mean that is different from 0 and a value of the standard deviation that is different from 1.

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2 years ago

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Ainat [17]

Answer: I believe it is B

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3 years ago