Systems of equation:substitution
1 answer:
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2 + d = 2 - 3(d- 5) - 2
First, cancel 2 on both sides. / Your problem should look like:
Second, expand. / Your problem should look like:
Third, simplify -3d + 15 - 2 to get -3d + 13. / Your problem should look like:
Fourth, add 3d to both sides. / Your problem should look like:
Fifth, add d + 3d to get 4d. / Your problem should look like:
Sixth, divide both sides by 4. / Your problem should look like:
Answer as fraction:
Answer as decimal:
First, cancel 2 on both sides. / Your problem should look like:
Second, expand. / Your problem should look like:
Third, simplify -3d + 15 - 2 to get -3d + 13. / Your problem should look like:
Fourth, add 3d to both sides. / Your problem should look like:
Fifth, add d + 3d to get 4d. / Your problem should look like:
Sixth, divide both sides by 4. / Your problem should look like:
Answer as fraction:
Answer as decimal:
