Ask question

Ask question

All categories

3 years ago

9

The length of a rectangle is 1 meter less than twice its width. The perimeter of the rectangle is 40 meters. What is the length

of the rectangle?

1 answer:

Alexeev081 [22]3 years ago

5 0

Answer:

2 or more

Step-by-step explanation:

thts not my answer and i dont understanding

You might be interested in

How do i do this help me pls

IceJOKER [234]

Answer:

Brackets always means multiply, you multiply the power and the 4 with the number power outside

That gives you 16v^18

Step-by-step explanation:

6 0

3 years ago

Can someone please help me out<br> ASAP I WILL GIVE OUT BRAINLY

SashulF [63]

Answer:

x = 9

Perimeter = 74

Area = 342

Step-by-step explanation:

First, find x. to do so, set your formula up as

18 = 8x - 54

18 + 54 = 8x

72 = 8x

72/8 = x

9 = x

Now that you have x, find your missing side

2x + 1 = y, x

2 * 9 + = y

19 = y

Your perimeter is P = 2(l+W)

P = 2(18 * 19)

P = 74

Your area is A = wl

A = 19 * 18

A = 342

3 0

3 years ago

Read 2 more answers

at 8:03 am there are 188 empty seats on the train. at 8:10 am there are 160 empty seats. the number of seats decreases by the sa

Vikentia [17]

Given:
8:03 = 188 empty seats
8:10 = 160 empty seat

188 - 160 = 28 empty seats
8:10 - 8:03 = 0:07 minutes

28 / 7 minutes = 4 empty seats per minute

8:00 - 8:03 = 3 minutes
3 minutes * 4 seats per minute = 12 seats

188 + 12 = 200 empty seats at 8:00

8:15 - 8:10 = 0:05 minutes
5 minutes * 4 seats per minute = 20 empty seats
160 - 20 = 140 empty seats at 8:15

200 - 120 = 80 empty seats
80 empty seats / 4 empty seats per minute = 20 minutes
120 empty seats at 8:20.

8:00 = 200 empty seats
200 / 4 = 50 minutes
8:00 + 0:50 = 8:50 is the time when there are no empty seats left.

6 0

4 years ago

Example 3 find the local maximum and minimum values and saddle points of f(x, y) = x4 + y4 − 4xy + 1. solution we first locate t

allsm [11]

$f(x,y)=x^4+y^4-4xy+1$

$\begin{cases}f_x=4x^3-4y\\f_y=4y^3-4x\end{cases}$

We have critical points whenever both partial derivatives vanish:

$4x^3-4y=0\implies x^3=y\implies x=y^{1/3}$
$4y^3-4x=0\implies y^3=x=y^{1/3}\implies y^6=y\implies y=0,y=-1,y=1$
$\begin{cases}y=0\implies x=0\\y=-1\implies x=-1\\y=1\implies x=1\end{cases}$

The Hessian is

$\mathbf H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}12x^2&-4\\-4&12y^2\end{bmatrix}$
$\det\mathbf H(x,y)=(12xy)^2-16$

At (0,0), we have $\det\mathbf H(0,0)=-16$ , so (0,0) is a saddle point.

At (-1, -1), we have $\det\mathbf H(-1,-1)=128>0$ and $f_{xx}(-1,-1)=12>0$ , so (-1, -1) is a local minimum.

At (1, 1), we have $\det\mathbf H(1,1)=128>0$ and $f_{xx}(1,1)=12>0$ , so (1, 1) is also a local minimum.

3 0

3 years ago

What is 0.045 kg * 90 m / s squared

serg [7]

Answer:

4.05 N

Step-by-step explanation:

A newton is kilograms times meters over seconds squared.

0.045 kg × 90 m/s² = 4.05 kg*m/s² = 4.05 N

5 0

4 years ago