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djverab [1.8K]
3 years ago
14

Please help. Algebra.

Mathematics
2 answers:
krok68 [10]3 years ago
7 0

Answer:

A I think so

Step-by-step explanation:

kirza4 [7]3 years ago
5 0
The correct answer would be C. This is because when you have a fraction that has variables with exponents, you can just subtract the exponents in the numerator from the denominator exponents. So, 4-2 is 2. Then you bring that down to the denominator and get the correct answer.

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Write in standard form: (5×100)+(6×1)+(5×1/10)+(9×1/1000)​
PIT_PIT [208]

Answer:

9,556

Step-by-step explanation:

5 0
3 years ago
Marking brainliest for a simple math problem​
nalin [4]

Answer:

B. 88

Step-by-step explanation:

the total data = 1+2+4+5 = 12

the median is (a6+a7) /2

a6 = 87, a7 = 89

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7 0
3 years ago
Please help i can not fail this!!
ivann1987 [24]
No solution 
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4 0
4 years ago
Read 2 more answers
Suppose that six individuals are interested in taking part in a study relating BMI to a number of health outcomes. The following
posledela

Answer:

a) Mean = 27.65

Median = 27.645

b) Relative Frequency = 33.33%

Step-by-step explanation:

We are given the following data set:

25.78, 21.06, 36.54, 29.51, 18.96, 34.05

a) Mean and Median

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{165.9}{6} = 27.65

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data: 18.96, 21.06, 25.78, 29.51, 34.05, 36.54

\text{Median} = \displaystyle\frac{25.78 +29.51}{2} = 27.645

b) BMI above 30 is considered obese

Frequency of obese in the given sample = 2

Relative Frequency =

\displaystyle\frac{\text{Frequency of obese}}{\text{Total number}} = \frac{2}{6} = 0.3333 = 33.33\%

5 0
3 years ago
(5 + 5) x 10 = ? for easy points<br><br> Wrong answers only!
erma4kov [3.2K]

Answer:

Omg its totally 726263893276273

7 0
3 years ago
Read 2 more answers
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