Please help. Algebra.

Mathematics

2 answers:

krok68 [10]3 years ago

7 0

Answer:

A I think so

Step-by-step explanation:

kirza4 [7]3 years ago

5 0

The correct answer would be C. This is because when you have a fraction that has variables with exponents, you can just subtract the exponents in the numerator from the denominator exponents. So, 4-2 is 2. Then you bring that down to the denominator and get the correct answer.

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Urgent!! Find an equivalent rational expression in lowest terms and identify the domain

JulsSmile [24]

1) domain: x cannot be -1/3, 0
2) domain: m cannot be 4/3, -7/2
3) domain: m cannot be 3

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3 years ago

This is really confusing me:<br> Simplify so that your answers contain only positive exponents.

xxTIMURxx [149]

Answer:

see below

Step-by-step explanation:

For simplifying expressions of this sort, there are four rules of exponents that come into play;

$a^ba^c=a^{b+c}\\\\(ab)^c=a^cb^c\\\\(a^b)^c=a^{bc}\\\\\dfrac{1}{a^b}=a^{-b}\ \quad\text{which means}\quad a^b=\dfrac{1}{a^{-b}}$

I find it convenient to eliminate the fractions by adding the exponents, then rewrite any negative exponents as denominator factors.

$23. \quad\dfrac{1}{x^{-2}}=x^2\\\\24. \quad\dfrac{mn}{m^2n^3}=m^{1-2}n^{1-3}=m^{-1}n^{-2}=\dfrac{1}{mn^2}\\\\25. \quad\dfrac{k^{-2}}{k^{-3}}=k^{-2-(-3)}=k\\\\26. \quad\left(\dfrac{m^2}{n^3}\right)^3=\dfrac{m^{2\cdot 3}}{n^{3\cdot 3}}=\dfrac{m^6}{n^9}\\\\27. \quad\dfrac{x^2y^3z^4}{x^{-3}y^{-4}z^{-5}}=x^{2-(-3)}y^{3-(-4)}z^{4-(-5)}=x^5y^7z^9$