2 years ago

F4f follow me on ig Fendimulatto Juicyminkz

Mathematics

1 answer:

Ira Lisetskai [31]2 years ago

4 0

Answer:

Step-by-step explanation:

ok i will follow because I can get points

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What is the value of f(5) in f(x)=-2(x+1)

IceJOKER [234]

Answer:

-12

Step-by-step explanation:

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2 years ago

A card is drawn at random from a standard deck of 52 cards. Find the following conditional probabilities. a) The card is a diam

Inga [223]

Answer:

$a.\frac{1}{13}\\b.\frac{1}{2}\\c.\frac{1}{13}\\d.\frac{1}{13}$

Step-by-step explanation:

P(A|B) = P(A and B) / P(B)

Total number of cards = 52

Let A denotes the event that the card is a diamond and B denotes the card is red.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}\\=\frac{\frac{2}{52}}{\frac{26}{52}}\\=\frac{1}{13}$

Let A denotes the event that the card is red and B denotes the card is diamond.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{2}{52}}{\frac{4}{52}}\\=\frac{1}{2}$

Let A denotes the event that the card is nine and B denotes the card is red.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{2}{52}}{\frac{26}{52}}\\=\frac{1}{13}$

Let A denotes the event that the card is a king and B denotes the card is a face card.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{4}{52}}{\frac{12}{52}}\\=\frac{1}{13}$

7 0

2 years ago

Can someone help me please and thankyou

Phantasy [73]

X° = 90°-29°
= 61°

y°= 90°- 61°
= 29°

find y and x right?

8 0

2 years ago

Melissa is standing 40 ft from a tree. The angle of elevation from where she is standing on the ground to the top of the tree is

bagirrra123 [75]

Tan(angle) = opposite length/ adjacent length

Tan(50) = h/40
h = 40 x tan(50)
h = 47.67 or 47.7 feet

3 0

2 years ago

Read 2 more answers

I will give the BRAINIEST!!!<br><br>Which of these statements best describes the relation shown?

ludmilkaskok [199]

Answer:

i believe the answer is C

Step-by-step explanation:

i dont know its just what i would choose im not the smartests in math

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2 years ago