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Alinara [238K]
2 years ago
5

The slope of the line is 4. which of the following is the point-slope form of the line

Mathematics
1 answer:
antoniya [11.8K]2 years ago
4 0

The point slope form of line is y+4 = -4( x+3)

<h3>What is point slope of form?</h3>

The point slope form is used to find the equation of the straight line which is inclined at a given angle to the x-axis and passes through a given point.

Given:

m=4

We know the general form is

y - b = -4(x - a)

So, from the graph attached below

b= -4, a= -3

So, y-(-4)= -4(x-(-3))

y+4 = -4( x+3)

Hence,  point slope form of line is y+4 = -4( x+3).

Learn more about tis concept here:

brainly.com/question/13436232

#SPJ1

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A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
3 years ago
Which of the following equations represents the graph shown?
Sonja [21]

Answer:

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Step-by-step explanation:

The slope is negative and the line intersects the y-intercept at positive 2.

5 0
3 years ago
Read 2 more answers
Enter the values to complete the statement. To determine whether (−1,4) (−1,4) is a solution to the equation 3x+8y=29 3x+8y=29 ,
aivan3 [116]
<span>To determine whether (−1,4) is a solution to the equation 3x+8y=29, substitute  ...-1... for x and ...4... and for y.


In a pair of values like (-1, 4), the first coordinate, or entry, occupied by -1 always represents x.

Similarly, the second coordinate occupied by 4 represents y.


Answer: </span>substitute  ...-1... for x and ...4... and for y.
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PLEASE HELP! I WILL MARK BRAINLIEST! Which type of lines is shown in the illustration above?
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D intersecting lines
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Please help I know how to do this but there’s too much
Lady_Fox [76]

Answer: See attached images

Step-by-step explanation:

For third period:

Minimum = 67

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I've attached the image for this class's box plot.

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Median/2nd Quartile: 88

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I've also attached the image for this class's box plot

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