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Fantom [35]
3 years ago
13

Can you measure surface area with square feet

Mathematics
1 answer:
Savatey [412]3 years ago
8 0

Answer:

My thinking is that <u>yes</u> you can.

Please let me know if there are certain answers that you can choose from for this question so that I can be more specific.

<h3><u>Hope this helps!</u></h3>
You might be interested in
Angle P is 3 more than twice angle M. If the two angles are complementary, find the measure of the two angles.
kotegsom [21]

Answer:

  • 29° and 61°

Step-by-step explanation:

<em>Complementary angles sum up to 90°</em>

<u>Given</u>

  • P + M = 90°
  • P = 2M + 3°

<u>Substituting P in the first equation</u>

  • 2M + 3° + M = 90°
  • 3M = 87°
  • M = 29°

<u>Then </u>

  • P = 90° - 29° = 61°
5 0
3 years ago
Read 2 more answers
How are (5.3,1) and (-5.3,1) related?
OleMash [197]

Answer:

i think because theyre like terms, im not sure tho

3 0
2 years ago
Find all the powers of 4 in the range of 4 through 1000
Nookie1986 [14]

4¹ = 4
4² = 16
4³ = 64
4⁴ = 256

(4⁵ = 1,024)


4 0
3 years ago
Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

Second=16a^{2}

Third=25a^{2}

Fourth=24a^{2}

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

7 0
3 years ago
Read 2 more answers
Simplify: (sin θ − cos θ)^2 − (sin θ + cos θ)^2 A) −4sin(θ)cos(θ) B) 2 C) sin^2 θ D) cos^2 θ
N76 [4]

Answer:

-4sinθcosθ

Step-by-step explanation:

Note:

1. (a + b)^2 = a^2 + 2ab + b^2

2. (a - b)^2 = a^2 - 2ab + b^2

3. sin^2θ + cos^2θ = 1

(sinθ -cosθ)^2 - (sinθ + cosθ)^2

= sin^2θ - 2sinθcosθ + cos^2θ - (sin^2θ + 2sinθcosθ + cos^2θ)

= sin^2θ + cos^2θ - 2sinθcosθ - (sin^2θ + cos^2θ + 2sinθcosθ)

= 1 - 2sinθcosθ - (1 + 2sinθcosθ)

= 1- 2sinθcosθ -1 - 2sinθcosθ

= - 2sinθcosθ - 2sinθcosθ

= -4sinθcosθ

3 0
3 years ago
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