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Mnenie [13.5K]
3 years ago
15

What is the constant of proportionality of

Mathematics
2 answers:
just olya [345]3 years ago
8 0
Number 5 because it is on the more
ehidna [41]3 years ago
3 0

Answer:

I couldn’t add all my solotions but u can make another question so I can give it to u

Step-by-step explanation:

But this are just the graph tell me if u need solutions

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Solve for x <br><br><br><br> I need helppppopopo
dolphi86 [110]

1.) the line makes triangle
2.) triangles always equal 180 degrees
3.)180-108-37=35
4.)35=8x+3
5.) 32=8x
6.)4=X
6 0
3 years ago
What is .825252525 repeating as a fraction
masya89 [10]
Let d = 0.825252525..., then
10d = 8.25252525...=8\frac{25}{10^2-1}=8\frac{25}{99}

Therefore,
d=\frac{8}{10}+\frac{25}{990}=\frac{8(99)+25}{990}=\frac{817}{990}
5 0
3 years ago
Kate paid $27 for a dress that was on sale for 10% off. What was the original price of this dress?
Luba_88 [7]
The best way to go about this questions is to write out a formula in which x represents the original price of the dress: x*0.90=27. To see where the 0.90 came from, if Kate's dress was 10% off, she must have paid 90% of the original price (100%-10%=90%). Then, to convert a percentage to a decimal, move the decimal point twice to the left so 90% becomes 0.90. Then, our formula essentially means that 90% of some number (x) is equal to 27. To solve for x, divide both sides of the formula by 0.90 to get x=$30 which is the final answer.

I hope this helps.
8 0
3 years ago
Read 2 more answers
Factor. -9nm^2-90n^2+81n^3
cluponka [151]
Find GCF:-

GCF of the  numbers = -9 

of terms in n GCF = n
 
GCF is -9n so factors are

-9n(m^2 + 10n - 9n^2)

4 0
3 years ago
A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic
stellarik [79]

Answer:

a) There is a 59.87% probability that none of the LED light bulbs are defective.

b) There is a 31.51% probability that exactly one of the light bulbs is defective.

c) There is a 98.84% probability that two or fewer of the LED light bulbs are defective.

d) There is a 100% probability that three or more of the LED light bulbs are not defective.

Step-by-step explanation:

For each light bulb, there are only two possible outcomes. Either it fails, or it does not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 10, p = 0.05

a) None of the LED light bulbs are defective?

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}*(0.05)^{0}*(0.95)^{10} = 0.5987

There is a 59.87% probability that none of the LED light bulbs are defective.

b) Exactly one of the LED light bulbs is defective?

This is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}*(0.05)^{1}*(0.95)^{9} = 0.3151

There is a 31.51% probability that exactly one of the light bulbs is defective.

c) Two or fewer of the LED light bulbs are defective?

This is

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = 2) = C_{10,2}*(0.05)^{2}*(0.95)^{8} = 0.0746

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.5987 + 0.3151 + 0.0746 0.9884

There is a 98.84% probability that two or fewer of the LED light bulbs are defective.

d) Three or more of the LED light bulbs are not defective?

Now we use p = 0.95.

Either two or fewer are not defective, or three or more are not defective. The sum of these probabilities is decimal 1.

So

P(X \leq 2) + P(X \geq 3) = 1

P(X \geq 3) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = 0) = C_{10,0}*(0.95)^{0}*(0.05)^{10}\cong 0

P(X = 1) = C_{10,1}*(0.95)^{1}*(0.05)^{9} \cong 0

P(X = 2) = C_{10,1}*(0.95)^{2}*(0.05)^{8} \cong 0

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0

P(X \geq 3) = 1 - P(X \leq 2) = 1

There is a 100% probability that three or more of the LED light bulbs are not defective.

8 0
3 years ago
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