Answer:
$52091.95
Step-by-step explanation:
From the given information:
The number of cities visited = 14
Cost of each cooking demonstration = $3450
The total cost of cooking demonstration = $3450 × 14
= $48300
Book signing material = $1475
∴
The total cost of cooking demonstration and book material is:
= $48300 + $1475 = $49775 ---- (i)
Total meter traveled in visiting 14 cities = 240 * 13 = 3120 miles
However; suppose the weekly rental fee fine = $x &
the change per mile = $y
Then
y*540 + x = 1188.15 --- (ii)
y*880 + x = 1310.55 --- (iii)
From equation (ii) and (iii)
y *340 = 122.4
y = 122.4/340
y = 0.36
From (ii)
y × 540 + x = 1188.15
(0.36)540 + x = 1188.15
x = 1188.15 - (0.36)540
x = 993.75
Hence, the total cost of travelling by RV camper = $1993.75 + 3120 × (0.36)
= $2116.95
Thus, the total amount the publisher should budget = $49975.0 + $2116.95
= $52091.95
It is either A or C just incase you needed an answer quickly
Answer:
1.236 × 10^(-3)
Step-by-step explanation:
Let A be the event that the person is a future terrorist
Let B the event that the person is identified as a terrorist
We are told that there are 1,000 future terrorists in a population of 400 million. Thus, the Probability that the person is a terrorist is;
P(A) = 1000/400000000
P(A) = 0.0000025
P(A') = 1 - P(A)
P(A') = 1 - 0.0000025
P(A') = 0.9999975
We are told that the system has a 99% chance of correctly identifying a future terrorist. Thus; P(B|A) = 0.99
Thus, P(B'|A) = 1 - P(B|A)
P(B'|A) = 1 - 0.99
P(B'|A) = 0.01
We are told that there is a 99.8% chance of correctly identifying someone who is not a future terrorist. Thus; P(B'|A') = 0.998
Hence: P(B|A') = 1 - P(B'|A')
P(B|A') = 1 - 0.998
P(B|A') = 0.002
We want to find the probability that someone who is identified as a terrorist, is actually a future terrorist. This is represented by: P(A|B)
We can find it from bayes theorem as follows;
P(A|B) = [P(B|A) × P(A)]/[(P(B|A) × P(A)) + (P(B|A') × P(A')]
Plugging in the relevant values;
P(A|B) = [0.99 × 0.0000025]/[(0.99 × 0.0000025) + (0.002 × 0.9999975)]
P(A|B) = 0.00123597357 = 1.236 × 10^(-3)
let's notice something, we have a circle with a radius of 12 and one 90° sector is cut off, so only three 90° sectors of the circle are left shaded, so namely the cone will be using 3/4 of that circle.
think of it as, this shaded area is some piece of paper, and you need to pull it upwards and have the cutoff edges meet, and when that happens, you'll end up with a cone-shaped paper cup, and pour in some punch.
now, once we have pulled up the center of the circle to make our paper cup, there will be a circular base, its diameter not going to be 24, it'll be less, but whatever that base is, we know that is going to have the same circumference as those in the shaded area. Well, what is the circumference of that shaded area?
![\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=12 \end{cases}\implies C=2\pi 12\implies C=24\pi \implies \stackrel{\textit{three quarters of it}}{24\pi \cdot \cfrac{3}{4}} \\\\\\ 6\pi \cdot 3\implies 18\pi](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bcircumference%20of%20a%20circle%7D%5C%5C%5C%5C%20C%3D2%5Cpi%20r~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D12%20%5Cend%7Bcases%7D%5Cimplies%20C%3D2%5Cpi%2012%5Cimplies%20C%3D24%5Cpi%20%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bthree%20quarters%20of%20it%7D%7D%7B24%5Cpi%20%5Ccdot%20%5Ccfrac%7B3%7D%7B4%7D%7D%20%5C%5C%5C%5C%5C%5C%206%5Cpi%20%5Ccdot%203%5Cimplies%2018%5Cpi)
well then, the circumference of that circle at the bottom will be 18π, so, what is the diameter of a circle with a circumferenc of 18π?
![\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=18\pi \end{cases}\implies 18\pi =2\pi r\implies \cfrac{18\pi }{2\pi }=r\implies 9=r \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{diameter is twice the radius}}{d=18}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bcircumference%20of%20a%20circle%7D%5C%5C%5C%5C%20C%3D2%5Cpi%20r~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20C%3D18%5Cpi%20%5Cend%7Bcases%7D%5Cimplies%2018%5Cpi%20%3D2%5Cpi%20r%5Cimplies%20%5Ccfrac%7B18%5Cpi%20%7D%7B2%5Cpi%20%7D%3Dr%5Cimplies%209%3Dr%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bdiameter%20is%20twice%20the%20radius%7D%7D%7Bd%3D18%7D~%5Chfill)
Answer:
i think it a or b but i might be wrong
Step-by-step explanation:
sry if it is wrong tho
