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3 years ago

Which equation is quadratic in form?

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

7 0

Answer:

6(x + 2)^2 + 8x + 2 + 1 = 0

Step-by-step explanation:

A quadratic equation has the variable with the highest power of 2

6(x + 2)^2 + 8x + 2 + 1 = 0 when foiled out it has the highest power of 2

6x4 + 7x2 – 3 = 0 power of 4

5x6 + x4 + 12 = 0 power of 6

x9 + x3 – 10 = 0 power of 9

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Karolina [17]

19.q 20.d 21.6/7 22.6/7 23.b

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4 years ago

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A ball is thrown into the air. The path it takes is modeled by the equation: -3t+24t = h, where t is the time in seconds and h i

astra-53 [7]

Given:

The given equation is:

$-3t^2+24t=h$

Where, t is the time in seconds and h is the height of the ball above the ground, measured in feet.

To find:

The inequality to model when the height of the ball is at least 36 feet above the ground. Then find time taken by ball to reach at or above 36 feet.

Solution:

We have,

$-3t^2+24t=h$

The height of the ball is at least 36 feet above the ground. It means $h\geq 36$ .

$-3t^2+24t\geq 36$

$-3t^2+24t-36\geq 0$

$-3(t^2-8t+12)\geq 0$

Splitting the middle term, we get

$-3(t^2-6t-2t+12)\geq 0$

$-3(t(t-6)-2(t-6))\geq 0$

$-3(t-2)(t-6)\geq 0$

The critical points are:

$-3(t-2)(t-6)=0$

$t=2,6$

These two points divide the number line in 3 intervals $(-\infty,2),(2,6),(6,\infty)$ .

Intervals Check point $-3(t-2)(t-6)\geq 0$ Result

$(-\infty,2)$ 0 $(-)(-)(-)=(-)$ False

$(2,6)$ 4 $(-)(+)(-)=+>0$ True

$(6,\infty)$ 8 $(-)(+)(+)=(-)$ False

The inequality is true for (2,6) and the sign of inequality is $\geq$ . So, the ball is above 36 feet between 2 to 6 seconds.

$6-2=4$

Therefore, the required inequality is $-3t^2+24t\geq 36$ and the ball is 36 feet above for 4 seconds.

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Find the value of x in 5rasised to power x=125

mestny [16]

5^3=125
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valina [46]

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Where are the asymptotes for the following function located? f(x)= 7/ x^2-2x-24

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