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Kisachek [45]
3 years ago
15

Which equation is quadratic in form?

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

6(x + 2)^2 + 8x + 2 + 1 = 0

Step-by-step explanation:

A quadratic equation has the variable with the highest power of 2

6(x + 2)^2 + 8x + 2 + 1 = 0  when foiled out it has the highest power of 2

6x4 + 7x2 – 3 = 0  power of 4

5x6 + x4 + 12 = 0 power of 6

x9 + x3 – 10 = 0  power of 9

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What is parallel to y=3x+1<br> you can only use the numbers 3,-2,1,4,-1,0,2,5 and put it in y= x +
DiKsa [7]

Answer:

y=3x+1

Step-by-step explanation:

A parallel line has the same slope as the other line.

y=mx+b, m is the slope

Thus in y=3x+1, m =3

y = 3x + b

plug in points (1, 4) to determine b

4 = 3(1) + b

4 = 3 + b

subtract 3 on both sides

4 - 3 = b

b = 1

y = 3x + 1

please give thanks by clicking heart button :)

4 0
3 years ago
At one gym, there is a $12 start-up fee, and after that each month, m, at the gym costs $20. At another gym, each month at the g
nata0808 [166]

Answer:

6 months

Step-by-step explanation:

Gym1

12 + 20m

Gym2

22m

Set them equal

12 +20m = 22m

Subtract 20 m from each side

12 +20m-20m = 22m-20m

12 = 2m

Divide by 2

12/2 = 2m/2

6 =m

5 0
4 years ago
5000/210= with the remainder as a fraction
Softa [21]
The answer is 23 4/5
6 0
3 years ago
Read 2 more answers
Heights of women have a​ bell-shaped distribution with a mean of 159159 cm and a standard deviation of 55 cm. using​ chebyshev's
GarryVolchara [31]
Uqwvjkklookhhgcxddssc
6 0
3 years ago
the 11th term in a geometric sequence is 48 and the common ratio is 4. the 12th term is 192 and the 10th term is what?
Soloha48 [4]

<u>Given</u>:

The 11th term in a geometric sequence is 48.

The 12th term in the sequence is 192.

The common ratio is 4.

We need to determine the 10th term of the sequence.

<u>General term:</u>

The general term of the geometric sequence is given by

a_n=a(r)^{n-1}

where a is the first term and r is the common ratio.

The 11th term is given is

a_{11}=a(4)^{11-1}

48=a(4)^{10} ------- (1)

The 12th term is given by

192=a(4)^{11} ------- (2)

<u>Value of a:</u>

The value of a can be determined by solving any one of the two equations.

Hence, let us solve the equation (1) to determine the value of a.

Thus, we have;

48=a(1048576)

Dividing both sides by 1048576, we get;

\frac{3}{65536}=a

Thus, the value of a is \frac{3}{65536}

<u>Value of the 10th term:</u>

The 10th term of the sequence can be determined by substituting the values a and the common ratio r in the general term a_n=a(r)^{n-1}, we get;

a_{10}=\frac{3}{65536}(4)^{10-1}

a_{10}=\frac{3}{65536}(4)^{9}

a_{10}=\frac{3}{65536}(262144)

a_{10}=\frac{786432}{65536}

a_{10}=12

Thus, the 10th term of the sequence is 12.

8 0
3 years ago
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