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scZoUnD [109]
3 years ago
13

Evaluate the expression below when x = 4 and y = -2 *

Mathematics
1 answer:
kozerog [31]3 years ago
6 0

Answer:

Evaluate the expression below when x = 4 and y = -2 *

hii your question is incomplete

can you please recheck once

there is no expression given

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AVprozaik [17]
The solution to this equation is x=4.6 because 19.32/4.2=4.6
8 0
3 years ago
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From given figure write the radiation between m and n.​
Ulleksa [173]

Answer:

see explanation

Step-by-step explanation:

m and n are same- side interior angles and sum to 180°

6 0
3 years ago
1.64 written as fraction in simplest form
erastovalidia [21]
1.64 =  \frac{1.64 \times 100}{1 \times 100} = \frac{164}{100} = \frac{41\times 4}{25\times 4} = \boxed {\frac{41}{25} }
8 0
3 years ago
The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.
Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

h(t)=-16t^2+80t+64

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A)  Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

so

For h(t)=0

-16t^2+80t+64=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+80t+64=0

so

a=-16\\b=80\\c=64

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}

t=\frac{-80\pm\sqrt{10,496}} {-32}

t=\frac{-80+\sqrt{10,496}} {-32}=-0.70

t=\frac{-80-\sqrt{10,496}} {-32}=5.70

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

-16t^2+80t+64=40

-16t^2+80t+24=0

Solve the quadratic equation

we have

a=-16\\b=80\\c=24

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}

t=\frac{-80\pm\sqrt{7,936}} {-32}

t=\frac{-80+\sqrt{7,936}} {-32}=-0.28

t=\frac{-80-\sqrt{7,936}} {-32}=5.28

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0
3 years ago
Please help me solve this equation
elena-s [515]

Answer:

m<U = 38degrees

Step-by-step explanation:

From the given diagram, <B = <U since both triangles are similar, hence;

Hence;

2y+2 = 3y-16

2y - 3y = -16 - 2

-y = -18

y = 18

Get m<U

m<U = 3y-16

m<U = 3(18) -16

m<U = 54 - 16

m<U = 38degrees

3 0
3 years ago
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