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Sliva [168]
3 years ago
8

Factor the expression using GCF of 4+22​

Mathematics
1 answer:
xxMikexx [17]3 years ago
6 0

Answer:

the answer would be 2(2+11)

Step-by-step explanation:

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2(5m^4n^-1)^3 simplify show work please
dangina [55]

Answer:

\large\boxed{2(5m^4n^{-1})^3=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}}

Step-by-step explanation:

\text{Use}\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\-------------------\\\\2(5m^4n^{-1})^3=2(5)^3(m^4)^3(n^{-1})^3=2(125)m^{3\cdot4}n^{-1\cdot3}=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}

8 0
3 years ago
Write each of the following expressions without using absolute value: PLEASE HELP I WILL MAKE BRAINLIEST TO WHOEVER GETS BOTH OF
nignag [31]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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Your teacher is choosing 2 students to run an errand for her. There are 12 girls and 10 boys in the class. What is the probabili
Ne4ueva [31]

Answer:

2/7

Step-by-step explanation:

There are 22 (12 + 10) total students in the class. That means that the chance of the first student picked being a girl is 12/22.

Now, we must calculate the chance of the next student to be picked <em>also </em>being a girl - however, there is a trap here! Remember that since a girl has been picked, the total student pool has decreased to 21 and and the total number of girls has decreased to 11. This means the new chance of girl being picked is 11/21.

To find the probability of both these events happening in conjunction, these fractions must be multiplied. 12/22 * 11/21 = 132/462, which simplifies to 2/7.

4 0
3 years ago
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My number has two periods. One 3,0 and 6 in that order the other contains the digits 0,9 and 5 in that order
Vsevolod [243]
3.06, and 0.95 are the numbers.
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3 years ago
Find the limit. (If an answer does not exist, enter DNE.)<br> lim ( (1/x)-(1/lxl)) <br> x→0^+
jek_recluse [69]

Answer:

0

Step-by-step explanation:

The + on the zero means the limit as x approaches 0 from the right side

\lim_{x \to 0^{+} } (\frac{1}{x} - \frac{1}{|x|})\\ \lim_{x \to 0^{+} } (\frac{1}{x} - \frac{1}{x})\\ \lim_{x \to 0^{+} } (0)\\0

4 0
2 years ago
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