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kotykmax [81]
2 years ago
5

Please answer, I'm doing a test and it is almost done!!!

Mathematics
2 answers:
garri49 [273]2 years ago
8 0
50

(e= 10 to the power of)
6.6e-2/3.3e-4= 3.3e4/6.6e2=0.5e2= 0.5x10^2=50
Murljashka [212]2 years ago
3 0

Answer:

200

Step-by-step explanation:

6.6 divided by 3.3 is 2

10^-2 divided by 10^-4 is 10^2 or 100

2 times 100 is 200

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Twice the difference between x and k is 2(x-k)
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100 POINTS + BRAINLIST
mojhsa [17]

Problem 1

Since point P is the tangent point, this means angle OPT is a right angle

angle OPT = 90 degrees

Let's use the Pythagorean theorem to find the missing side 'a'

a^2 + b^2 = c^2

a^2 + 7^2 = 12^2

a^2 + 49 = 144

a^2 = 144 - 49

a^2 = 95

a = sqrt(95)

a = 9.7467943

a = 9.7

----------------

Let's use the sine and arcsine rule to find angle y

sin(angle) = opposite/hypotenuse

sin(y) = 7/12

y = arcsin( 7/12 )

y = 35.6853347

y = 35.7

The value of y is approximate. Make sure your calculator is in degree mode. Arcsine is the same as inverse sine or \sin^{-1}

====================================================

Problem 2

Focus on triangle OHP. This may or may not be a right triangle. The goal is to test if it is or not.

We use the converse of the Pythagorean theorem to check.

Recall that the converse of the Pythagorean theorem says: If a^2+b^2 = c^2 is a true equation, then the triangle is a right triangle. The value of c is always the longest side. The order of a and b doesn't matter.

In this case we have

  • a = 7
  • b = 13
  • c = 16

Which leads to

a^2 + b^2 = c^2

7^2 + 13^2 = 16^2

49 + 169 = 256

218 = 256

We get a false equation at the end, since both sides aren't the same number, which means the original equation is false.

We don't get a^2 + b^2 = c^2 to be true, therefore this triangle is not a right triangle.

Consequently, this means angle OPH cannot possible be 90 degrees (if it was then we'd have a right triangle). Therefore, point P is not a tangent point.

You follow the same basic idea for triangle OQH and show that point Q is not a tangent point either. Or you could use a symmetry argument to note that triangle OPH is a mirror reflection of triangle OQH over the line segment OH. This implies that whatever properties triangle OPH has, then triangle OQH has them as well for the corresponding pieces.

7 0
2 years ago
Read 2 more answers
Solve the conjunction and describe the solution set.
BaLLatris [955]
 -5 ≤ 3m + 1 < 4
- 1           - 1  - 1
 -6 ≤ 3m < 3
  3      3     3
 -2 ≤ m < 1

Solution Set: {m|-2 ≤ m < 1}, {m|m ≥ -2 and m < 1}, [-2, 1)

The answer is A.
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3 years ago
A recipe calls for 2/5 cup of chicken broth and 1/6 cup of vegetable broth. What is the total amount of broth need for the recip
Bess [88]

Answer:

I may not be correct, depending on what you were taught, but it would be...

17/30

Step-by-step explanation:

(2/5×6/6)+(1/6×5/5)

12/30 + 5/30

17/30

keep in mind you don't add the denominators at all ( the numbers at the bottom half of the fraction)

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Identify the term that completes the equation. AC^2 = (DC)(?)<br><br> BC<br> AD<br> BD<br> AB
fiasKO [112]

Answer:

BC

Step-by-step explanation:

the height of a right-angled triangle to the Hypotenuse is the square root of the product of the lengths of the 2 segments of the Hypotenuse.

so the square of the height is then the product of the 2 line segments of the Hypotenuse.

therefore

AC² = DC × BC

3 0
2 years ago
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