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In-s [12.5K]
3 years ago
5

Use the distributive property to write an equivalent expression of the following

Mathematics
2 answers:
Nina [5.8K]3 years ago
8 0

Answer:

2b+2c

35h+15m

4x+4y

3ac+bc

scoray [572]3 years ago
5 0

Answer:

Solution given:

2 ( b + c )=2b+2c

5 (7h + 3m)=35h+15m

4 (x+y)=4x+4y

c ( 3a + b )=3ac+bc

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Simplify each expression to a single trig function or number cosx(secx-cosx)
AlladinOne [14]
I did this test  b4, yours is answer #number 12

Convert things to their basic forms. 
<span>Remember a few identities </span>
<span>sin^2 + cos^2 = 1 so </span>
<span>sin^2 = 1 - cos^2 and </span>
<span>cos^2 = 1 - sin^2 </span>

<span>I'm going to skip typing the theta symbol, just to make things faster. Just assume it is there and fill it in as you work the problems. </span>

<span>Follow along to see how each problem was worked out. You'll catch on to the general technique. </span>

<span>====== </span>
<span>1. sec θ sin θ </span>
<span>1/cos * sin = sin/cos = tan </span>

<span>2. cos θ tan θ </span>
<span>cos * sin/cos = sin </span>

<span>3. tan^2 θ- sec^2 θ </span>
<span>sin^2 / cos^2 - 1/cos^2 </span>
<span>(sin^2 - 1)/cos^2 </span>
<span>-(1-sin^2)/cos^2 </span>
<span>-cos^2/cos^2 </span>
<span>-1 </span>

<span>4. 1- cos^2θ </span>
<span>sin^2 </span>

<span>5. (1-cosθ)(1+cosθ) </span>
<span>Remember (a+b)(a--b) = a^2 - b^2 </span>
<span>1-cos^2 = sin^2 </span>

<span>6. (secx-1) (secx+1) </span>
<span>sec^2 -1 </span>
<span>1/cos^2 - 1 </span>
<span>1/cos^2 - cos^2/cos^2 </span>
<span>(1-cos^2)/cos^2 </span>
<span>sin^2/cos62 </span>
<span>tan^2 </span>

<span>7. (1/sin^2A)-(1/tan^2A) </span>
<span>1/sin^2 - 1/(sin^2/cos^2) </span>
<span>1/sin^2 - cos^2/sin^2 </span>
<span>(1-cos^2)/sin^2 </span>
<span>sin^2/sin^2 </span>
<span>1 </span>

<span>8. 1- (sin^2θ/tan^2θ) </span>
<span>1-sin^2/(sin^2/cos^2) </span>
<span>1 - sin^2*cos^2/sin^2 </span>
<span>1-cos^2 </span>
<span>sin^2 </span>


<span>9. (1/cos^2θ)-(1/cot^2θ) </span>
<span>1/cos^2 - 1/(cos^2/sin^2) </span>
<span>1/cos^2 - sin^2/cos^2 </span>
<span>(1-sin^2)/cos^2 </span>
<span>cos^2/cos^2 </span>
<span>1 </span>

<span>10. cosθ (secθ-cosθ) </span>
<span>cos *(1/cos - cos) </span>
<span>1-cos^2 </span>
<span>sin^2 </span>

<span>11. cos^2A (sec^2A-1) </span>
<span>cos^2 * (1/cos^2 - 1) </span>
<span>1 - cos^2 </span>
<span>sin^2 </span>


<span>12. (1-cosx)(1+secx)(cosx) </span>
<span>(1-cos)(1+1/cos)cos </span>
<span>(1-cos)(cos + 1) </span>
<span>-(cos-1)(cos+1) </span>
<span>-(cos^2 - 1) </span>
<span>-(-sin^2) </span>
<span>sin^2 </span>

<span>13. (sinxcosx)/(1-cos^2x) </span>
<span>sin*cos/sin^2 </span>
<span>cos/sin </span>
<span>cot </span>

<span>14. (tan^2θ/secθ+1) +1 </span>
<span>(sin^2/cos^2)/(1/cos) + 2 </span>
<span>sin^2/cos + 2 </span>
<span>sin*tan + 2 </span>
5 0
3 years ago
Larry made 4 batches of punch. Each Batch uses 16 fluid oz of lemon juice and 3 pints of orange juice. If each serving is 1 cup
Nikitich [7]
He made 32 servings. 

16 ounces + 3 pints=64 fluid ounces. 
64 fluid ounces=8 cups
8x4=32
6 0
3 years ago
Read 2 more answers
What number has the same value as 28 tens
Digiron [165]
You would multiply 28 times 10 which equals 2,800
4 0
3 years ago
Read 2 more answers
What is the mistake loki made?
DerKrebs [107]
Answer:
Loki didn’t square a and b

Answer explained:
Pythagorean Theorem is a^2 + b^2 = c^2
5 0
4 years ago
Eileen’s cookies charges $0.40 per cookie with a delivery fee of $8. Insomnia cookies charges $1.50 per cookie with a $2.50 deli
Nuetrik [128]

Answer: 5 cookies

Step-by-step explanation:  8 + .4c = 2.5 + 1.5c

8 + 0.4c = 2.5 + 1.5c

8 · 10 + 0.4c · 10 = 2.5 · 10 + 1.5c · 10

80 + 4c = 25 + 15c

4c = 15c - 55

4c - 15c = 15c - 55 - 15c

-11c = -55

c = 5

8 0
4 years ago
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