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natali 33 [55]
3 years ago
12

number of bacteria in a certain population Increases according to a continuous exponential growth model with How many hours does

it take the size of the sample to double ? growth rato parameter of 48% per hour
Mathematics
1 answer:
vladimir1956 [14]3 years ago
3 0

Answer:

It takes 1.77 hours for the population to double.

Step-by-step explanation:

Equation for population growth:

The equation for population growth, after t hours, with a growth rate parameter of r, as a decimal, is given by:

P(t) = P(0)(1+r)^t

Growth rato parameter of 48% per hour

This means that r = 0.48. So

P(t) = P(0)(1+r)^t

P(t) = P(0)(1+0.48)^t

P(t) = P(0)(1.48)^t

How many hours does it take the size of the sample to double?

This is t for which P(t) = 2P(0). So

P(t) = P(0)(1.48)^t

2P(0) = P(0)(1.48)^t

(1.48)^t = 2

\log{(1.48)^t} = \log{2}

t\log{1.48} = \log{2}

t = \frac{\log{2}}{\log{1.48}}

t = 1.77

It takes 1.77 hours for the population to double.

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Answer:  Dilated and then translated

Step-by-step explanation:

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2 years ago
A consumer charges a $50 purchase on a credit card. The card has a daily interest rate of 0.038%. If the consumer pays off the b
Mariana [72]

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4 0
2 years ago
If the width and length of a rectangle are both increased by 10%, by what percent does the area of the rectangle increase?
S_A_V [24]

Answer:

10%

Step-by-step explanation:

We know Perimeter of rectangle

= 2 (Length + Width)

If width and length are increased by 10%

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New width = W + 10/100W = (1.1) W

Perimeter = 2 [(1.1) L + (1.1) W]

Perimeter = 2 (1.1) (L + W)

Perimeter = (2.2) (L + W)

Increase in perimeter = 2.2 (L + W) - 2 (L + W)

The increase in Perimeter = 0.2 (L + W)

Percent increase

= 0.2 (L + W)/2 (L + W) × 100

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I hope this helped and if it did, please mark as Brainliest.

7 0
3 years ago
Need help simplifying this
diamong [38]

The simplified answer is \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}.

<u>Step-by-step explanation:</u>

$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term (\frac{3x+y}{3x+y}) and 2nd term by (\frac{z+2x}{z+2x})

= \frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= \frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}

Now, the denominators are same, you can subtract it.

= \frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

= \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

Thus the simplified solution is  \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

4 0
3 years ago
Jessica and Riley are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping
bixtya [17]

Answer:

Cost of one roll of plain wrapping: \$5

Cost of one roll of holiday wrapping paper:  \$19

Step-by-step explanation:

Let be "p" the cost in dollars of one roll of plain wrapping paper and "h" the cost in dollars of one roll of holiday wrapping paper.

Based on the information given, we can set up this system of equations:

\left \{ {{5p+13h=272} \atop {11p+16h=359}} \right.

In order to solve it, we can use the Substitution method. The steps are:

1. Solve for "p" from the first equation:

5p+13h=272\\\\5p=272-13h\\\\p=\frac{272-13h}{5}

2. Substitute the above into the second equation and solve for "h":

11(\frac{272-13h}{5})+16h=359\\\\598.4-28.6h+16h=359\\\\-12.6h=359-598.4\\\\h=\frac{-239.4}{-12.6}\\\\h=19

3. Substitute the value of "h" into p=\frac{272-13h}{5}:

p=\frac{272-13(19)}{5}\\\\p=5

7 0
3 years ago
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