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Alla [95]
3 years ago
6

you are about take an 8 question multiple choice test .each of these questions has 4 answers (A,B,C,D). how many ways can you an

swer the test if you leave an answer for each question
Mathematics
2 answers:
spin [16.1K]3 years ago
6 0

4^8 = 65536 answer is correct

Leviafan [203]3 years ago
5 0

4^8=65536

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What does 4C3 equal?
Hatshy [7]
I believe that would be 64C.
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4 years ago
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What are the measures of Angles a, b, and c? Show your work and explain your answers.<br> 25 points
bogdanovich [222]

Answer:

a=40

b=50

c= 115

Step-by-step explanation:

The first angle we will find is angle c

65 and angle c make a straight line so they add to 180

c+65 = 180

Subtract 65 from each side

c+65 -65 =180-65

c = 115


Angle a and 40 are vertical angles

Vertical angles are equal

angle a = 40


The sum of the angles in a triangle are equal to 180

a+b+ right angle = 180

40+ b + 90 = 180

130 +b = 180

Subtract 130 from each side

130-130+b = 180-130

b= 50

5 0
3 years ago
Find the value of the d. 2d - 5 = 17
LenKa [72]

Answer:

d = 11

Step-by-step explanation:

Isolate the variable (d). Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, add 5 to both sides

2d - 5 (+5) = 17 (+5)

2d = 17 + 5

2d = 22

Next, divide 2 from both sides

(2d)/2 = (22)/2

d = 22/2

d = 11

11 is your answer for d.

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6 0
3 years ago
Dominic is solving the equation 2 (y-2) = 4 (y-3) + 4. His steps are shown below.
Zanzabum

Answer:

Step 2

Step-by-step explanation:

6 0
4 years ago
Calculate the value for each determinant:
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

\begin{vmatrix}3 & -1\\ -3 & 4\end{vmatrix}=(3\times 4)-(-1)\times (-3)

               = 12 - 3

               = 9

\begin{vmatrix}8 & -1\\ -4 & -1\end{vmatrix}=8\times(-1)-(-1)\times(-4)

               = -8 - 4

               = -12

\begin{vmatrix}-12 & -1\\ 12 & 5\end{vmatrix}=(-12)\times(5)-(-1)\times(12)

                = -60 + 12

                = -48

\begin{vmatrix}2 & -1\\ 2 & -1\end{vmatrix}=2\times(-1)-(2)\times(-1)

            = -2 + 2

            = 0

\begin{vmatrix}0 & -1\\ 17 & 4\end{vmatrix}=0\times(4)-(-1)\times(17)

              = 17

\begin{vmatrix}1 & 0\\ 0 & 1\end{vmatrix}=1\times(1)-(0)\times(0)

          = 1

6 0
3 years ago
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