Question

There are 7 cards with a picture of a rose and 2 cards with a picture of a daisy. Alfa keeps all the cards face down on the table with the pictures hidden and mixes them up. She then turns over one card face up and finds the picture of a rose on it. She removes this card from the table and turns over another card without looking. What is the probability that the card that Alfa turns over has a rose on it? 6 over 9 6 over 8 7 over 9 7 over 8

Answer 1

The answer would be 6/8 because she has already taken out one of the rose cards, so now you're only left with 8 cards. There are still 2 daisy cards, so you would subtract 8 by 2 and get 6. This makes it 6/8.

Answer 2

Answer: $\dfrac{6}{8}$ or 6 over 8.

Step-by-step explanation:

Given: The number of card having rose on it  = 7

The number of card having daisy on it = 2

Then the total number of cards on table = $7+2=9$

After removing one rose card , the total number of cards left on table = 8

The number of rose card left on table = 6

Now, the required probability is given by :-

$\text{P(Rose)}=\dfrac{\text{Number of rose card }}{\text{Total cards}}\\\\\Rightarrow\text{P(Rose)}=\dfrac{6}{8}$

Hence, the probability that the card that Alfa turns over has a rose on it = $\dfrac{6}{8}$