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vodomira [7]
3 years ago
12

There are 7 cards with a picture of a rose and 2 cards with a picture of a daisy. Alfa keeps all the cards face down on the tabl

e with the pictures hidden and mixes them up. She then turns over one card face up and finds the picture of a rose on it. She removes this card from the table and turns over another card without looking. What is the probability that the card that Alfa turns over has a rose on it? 6 over 9 6 over 8 7 over 9 7 over 8
Mathematics
2 answers:
VladimirAG [237]3 years ago
4 0
The answer would be 6/8 because she has already taken out one of the rose cards, so now you're only left with 8 cards. There are still 2 daisy cards, so you would subtract 8 by 2 and get 6. This makes it 6/8.
vekshin13 years ago
4 0

Answer: \dfrac{6}{8} or 6 over 8.

Step-by-step explanation:

Given: The number of card having rose on it  = 7

The number of card having daisy on it = 2

Then the total number of cards on table = 7+2=9

After removing one rose card , the total number of cards left on table = 8

The number of rose card left on table = 6

Now, the required probability is given by :-

\text{P(Rose)}=\dfrac{\text{Number of rose card }}{\text{Total cards}}\\\\\Rightarrow\text{P(Rose)}=\dfrac{6}{8}

Hence, the probability that the card that Alfa turns over has a rose on it = \dfrac{6}{8}

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