Answer: 3 - 7x/5
Explanation: move all terms that don’t contain y to the right side and solve.
Answer:
Step-by-step explanation:
The team draws with a probability of 1 = (0.5 + 0.2) = 0.3
If the team does not win then it loses or draws.
Loosing = 0.2
Draw := 0.3
P(not win) = 0.2 + 0.3 = 0.5
======================
Not lose means wins or draws.
P(not lose) = 0.5 + 0.3 = 0.8
======================
Not Draw means wins or loses
P(not draw) = 0.5 + 0.2 = 0.7
Of course all of these could be done more directly.
P(not win)= (1 - win) = 1- 0.5 = 0.5
P(not lose) = ( 1 - lose) = 1 - 0.2 = 0.8
P(not draw) = (1 - 0.3) = 0.7
It's a, because an exponent means it's multiplied by itself that many times. so 3 times 3 is 9 then times 3 again is 27. but negative exponents are always fractions and since the normal number is positive it's D (sorry at first I didn't see d and c)
By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
<h3>How to solve a system of equations</h3>
In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:
x - y = 5 (1)
x² · y = 5 · x + 6 (2)
By (1):
y = x + 5
By substituting on (2):
x² · (x + 5) = 5 · x + 6
x³ + 5 · x² - 5 · x - 6 = 0
(x + 5.693) · (x - 1.430) · (x + 0.737) = 0
There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737
And the y-values are found by evaluating on (1):
y = x + 5
x₁ ≈ 5.693
y₁ ≈ 10.693
x₂ ≈ 1.430
y₂ ≈ 6.430
x₃ ≈ - 0.737
y₃ ≈ 4.263
By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
To learn more on nonlinear equations: brainly.com/question/20242917
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Answer:
93°, 89°, 93°
Step-by-step explanation:
∠1 and ∠4 are supplementary angles:
m∠1 + m∠4 = 180°; m∠1 = 93°
∠2 and ∠4 are vertical angles:
m∠2 = m∠4 = 87°
∠3 and ∠4 are supplementary angles:
m∠3 + m∠4 = 180°; m∠3 = 93°
