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likoan [24]
3 years ago
10

Please answer this correctly

Mathematics
1 answer:
Dahasolnce [82]3 years ago
8 0

Answer:

9 5/7

Step-by-step explanation:

You add all the 13/14 then divided it by 14

Then add all the while numbers then add then add them all together

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A right triangle has a base of 11 yards and a height of 7 yards . If you were to construct a similar but not congruent right tri
Dimas [21]

Answer:

bae of 44 yds and a height of 28 yds

Step-by-step explanation:

11x7 = 88 yd^2 = area of small triangle

616/88 = 16 so the larger triangle area is 16 times larger than the smaller triangle.

The area of a triangle is not proportional to it's dimensions. An increase of 16 times the area only increases the dimensions by 4 times.

larger triangle dimensions are 11 x 4 = 44 and 7 x 4 = 28

5 0
3 years ago
1. What is the domain of the function graphed below?
Nimfa-mama [501]

Answer:

D. 0<x<5

Step-by-step explanation:

3 0
3 years ago
We want to find the zeros of this polynomial <br> Graph the zeros
mote1985 [20]

Answer:

intersection of the y axis

7 0
3 years ago
Find the zeros of the quadratic function: y= 6(7x + 9)(8x - 3).
fiasKO [112]

Answer:

A) (-9/7,0), (3/8,0)

Step-by-step explanation:

Zeros of a quadratic function:

x for which y = 0.

In this question:

y = 6(7x + 9)(8x - 3)

It's 0 if one of the factors is 0. 6 is never 0, now about the other to:

7x + 9 = 0

7x = -9

x = -\frac{9}{7}

So (-9/7, 0) is a zero of the quadratic function.

The other is:

8x - 3 = 0

8x = 3

x = \frac{3}{8}

(3/8,0) is the other zero.

Thus, the correct answer is given by option A.

6 0
2 years ago
A grocery store will only accept yellow onions that are at least 2.75 in. In diameter. A grower has a crop of onions with diamet
Paraphin [41]

Answer:

Step-by-step explanation:

Calculate z-score firstly

z-score = (x-mean)/SD = (2.75-2.5)/0.25 = 0.25/0.25 = 1

P( x greater than or equal to 2.75) = P(z greater than or equal to 1)

= 1 - p(z <1)

P(z<1) from table = 0.84134

1-p(z<1) = 0.15866 or 15.866%

4 0
3 years ago
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