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KiRa [710]
3 years ago
15

Slope-intercept form of the line that goes through the points (-9, 10) and (-7, 2)

Mathematics
2 answers:
ZanzabumX [31]3 years ago
8 0
Y=-4x-26
2-10/-7-(-9)
2-10/-7+9
-8/2
-4 slope
y-10=-4(x-(-9))
y-10=-4(x+9)
y-10=-4x-36
y=-4x-36+10
y=-4x-26
Lady_Fox [76]3 years ago
7 0
The answer is Y=-4x-26
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Answer:

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Step-by-step explanation:

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2 years ago
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What is the answer of 3[4(2³)-5²+7(8+4²)-16]?
Montano1993 [528]

<span>3[4(23)-52+7(8+42)-16]</span>

<span>3 x (4 x 8 - 52 + 7 x (8 + 42) - 16)</span>

<span>3 x (32 - 52 + 7 x (8 + 42) - 16)</span>

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8 0
3 years ago
Give the excluded values for the rational equation.<br><br> (3x)/(x-4)-(x+3)/(x+4)=(2x+7)/(x^(2)-16)
scoray [572]

\frac{3x}{x-4}  - \frac{x+3}{x-4} = \frac{2x+7}{x^2-16}

We factor the denominators

Factor x^2 - 16

x^2 - 4^2

We use a^2 - b^2 = (a+b)(a-b)

so x^2 - 4^2 = (x+4)(x-4)

Replace it in the given equation

\frac{3x}{x-4}  - \frac{x+3}{x-4} = \frac{2x+7}{(x+4)(x-4)}

Excluded values are the values that makes the denominator 0

we have (x-4)  and (x+4) in the denominator

We set the denominator =0 and solve for x

x-4 =0

Add 4 on both sides

x= 4

x+4=0

subtract 4 onboth side

so x= -4

Excluded values are x=-4 and x=4




8 0
3 years ago
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Mandarinka [93]
Numbers are 3 and 12
The product is 36
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3 years ago
What are the excluded values? b = 0 and -10 b = 2 and 5 b = 3 and 7 none of the above
Dominik [7]

b= 2 and 5

is your answer to the above question.

8 0
2 years ago
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