All categories

3 years ago

Can someone help me?

Mathematics

1 answer:

Sergio [31]3 years ago

3 0

9514 1404 393

Answer:

tan B = 12/5
cos B = 5/13
sin B = 12/13

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the applicable ratios:

Tan = Opposite/Adjacent ⇒ tan B = CA/CB = 12/5

Cos = Adjacent/Hypotenuse ⇒ cos B = BC/BA = 5/13

Sin = Opposite/Hypotenuse ⇒ sin B = AC/AB = 12/13

You might be interested in

A drag racer has two parachutes, a main and a backup, that are designed to bring the vehicle to a stop after the end of a run. S

sweet-ann [11.9K]

Answer:

the probability that one parachute deploys is P(one parachute deploys)= 0.9988 (99.88%)

Step-by-step explanation:

for event A= first parachute deploys , then P(A)=0.97

for event B= second parachute deploys, then

P(C∩B)= P(B/C)*P(C)

where

event C= first parachute fails

P(C) = 1-P(A)= 1-0.97 =0.03

P(B/C) = probability that second parachute deploys, when the fist one fails =0.96

P(C∩B)= probability that fist parachute fails and second parachute deploys

then

P(C∩B)= P(B/C)*P(C)=0.03*0.96 = 0.0288

then

P(one parachute deploys)= P(A) + P(C∩B) - P(A∩(C∩B)) ,

but since A and C are mutually exclusive events P(A∩(C∩B)) =0

thus

P(one parachute deploys)= P(A) + P(C∩B) =0.97 + 0.0288 = 0.9988

P(one parachute deploys)= 0.9988

6 0

3 years ago

A family of four baked two pizzas. Dad ate 1/2

Ghella [55]

Answer:1/2×4=2

1/3×4=4/3

Step-by-step explanation:

if I'm wrong then I'm sorry. and umm I think the question is not complete

5 0

3 years ago

The attendance at baseball games at a certain stadium is normally distributed, with a mean of 30,000 and a standard deviation of

lakkis [162]

Answer:

a) 0.964

b) 0.500

c) 0.885

d) $x \geq 32467.5$

e) 0.997

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 30000

Standard Deviation, σ = 1500

We are given that the distribution of attendance at stadium is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(attendance is greater than 27,300)

P(x > 27300)

$P( x > 27300) = P( z > \displaystyle\frac{27300 - 30000}{1500}) = P(z > -1.8)$

$= 1 - P(z \leq -1.8)$

Calculation the value from standard normal z table, we have,

$P(x > 27300) = 1 - 0.036 = 0.964 = 96.4\%$

b) P(attendance greater than or equal to 30000)

$P(x > 30000) = P(z > \displaystyle\frac{30000-30000}{1500}) = P(z \geq 0)\\\\P( z \geq 0) = 1 - P(z \leq 0)$

Calculating the value from the standard normal table we have,

$1 - 0.500 = 0.500 = 50\%$

c) P(attendance between 27000 and 32000)

$P(27000 \leq x \leq 32000) = P(\displaystyle\frac{27000 - 30000}{1500} \leq z \leq \displaystyle\frac{32000-30000}{1500}) = P(-2 \leq z \leq 1.33)\\\\= P(z \leq 1.33) - P(z < -2)\\= 0.908 - 0.023 = 0.885 = 88.5\%$

$P(27000 \leq x \leq 32000) = 88.5\%$

e) P(attendance less than 33000)

P(x < 33000)

$P( x < 33000) = P( z < \displaystyle\frac{33000 - 30000}{1500}) = P(z < 2)$

Calculating the value from the standard normal table we have,

P(x < 33000) = 0.997 = 99.7%

d) We have to find x such that:

$P( X > x) = P( z > \displaystyle\frac{x - 30000}{1500}) = 0.95$

Calculating the value from the standard normal table we have,

P(z = 1.645) = 0.95

Thus,

$\displaystyle\frac{x - 30000}{1500} \geq 1.645\\\\x \geq 32467.5$

The attendance should be greater than or equal to 32467.5 to be in the top 5% of all games.

6 0

4 years ago

Please help me <br> Find x

Elden [556K]

Your question has been heard loud and clear.

This is a right triangle , which means it has a hypotenuse ( longest side of the triangle)

X is the length of the hypotenuse. We need to find x.

By Pythagoras theorem ,

Side^2+side^2= Hypotenuse^2

2.5^2+3^2= x^2

= 6.25+9=x^2

15.25=x^2

So , x = root of 15.25 = 3.9

Therefore , x= 3.9

Thank you

3 0

4 years ago

Read 2 more answers

Is 3 1/4 closer to 3 or 4<br><br><br>is 3 3/5 closer to 3 or 4

agasfer [191]

Answer:3 and 1/4 is closer to 3 and 3/5 is closer to 4

Step-by-step explanation: one is closer on the number scale then the other

3 0

3 years ago