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Angelina_Jolie [31]
3 years ago
14

Can someone help me?

Mathematics
1 answer:
Sergio [31]3 years ago
3 0

9514 1404 393

Answer:

  • tan B = 12/5
  • cos B = 5/13
  • sin B = 12/13

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the applicable ratios:

  Tan = Opposite/Adjacent   ⇒   tan B = CA/CB = 12/5

  Cos = Adjacent/Hypotenuse   ⇒   cos B = BC/BA = 5/13

  Sin = Opposite/Hypotenuse   ⇒   sin B = AC/AB = 12/13

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What is the constant of proportionality for y=5/8x
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Which algebraic expression is equivalent to this expression?
Eduardwww [97]

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a

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3 years ago
Jennifer serves the volleyball to Marsha with an upward velocity of 10.5 ft/s. The ball is 5 feet above the ground when she stri
Katarina [22]

Answer:

  0.98 seconds

Step-by-step explanation:

We assume the height of the volleyball is described by the equation for ballistic motion. We want to find the time it takes for the height to become zero.

__

<h3>motion equation</h3>

The general form of the equation of height for ballistic motion is ...

  h(t)=-16t^2+v_0t+h_0\qquad\text{$v_0$ and $h_0$ are the initial velocity and height}

The coefficient 16 in the equation is an approximation of 1/2g, where g is the acceleration due to gravity in ft/s². This means the units of time and distance are expected to be seconds and feet.

For the problem at hand, the initial velocity and height are 10.5 ft/s and 5 ft. Then the height equation is ...

  h(t) = -16t² +10.5t +5

__

<h3>reaction time</h3>

Marsha has until the ball hits the ground to react to the serve. To find out how long that is, we need to solve the height equation for t when h=0. This is most easily done using the quadratic formula with ...

  • a = -16
  • b = 10.5
  • c = 5

The solution is ...

  t=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}= \dfrac{-10.5\pm\sqrt{10.5^2-4(-16)(5)}}{2(-16)}\\\\=\dfrac{10.5\pm\sqrt{430.25}}{32}=\dfrac{21\pm\sqrt{1721}}{64}

The positive solution is ...

  t ≈ 0.976327 ≈ 0.98

Marsha has about 0.98 seconds to react before the volleyball hits the ground.

_____

<em>Additional comment</em>

After about 0.33 seconds, Marsha knows she doesn't need to react at all. The serve will not clear the net. Its maximum height is about 6' 8 5/8". A women's volleyball net is 7' 4 1/8" high. Jennifer's serve velocity must be at least 12.3 ft/s for the ball to go over the net. With that upward velocity, Marsha has about 1.06 seconds to react.

4 0
2 years ago
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