Guys help me please!

Mathematics

1 answer:

steposvetlana [31]3 years ago

4 0

Answer:

Step-by-step explanation:

Suppose you are standing on a street corner. Suppose that you are counting cars. You notice that there are only black ones and white ones. For every 3 black cars there are 4 white ones. Beginning ratios always look something like this.

Black to white = 3 to 4

This is more commonly written in two ways

Black to White = 3/4
Black:White:: 3:4

So what do you notice? You should see that a ratio is a fraction.

All ratios are fractions.

Now suppose you are still on the street counting cars again. Suppose you notice that after counting 70 cars, you get

Black to White = 30:40
Is that still 3/4?
The answer is yes. You can multiply 3/4 by the same number on the top as you did on the bottom.

That's as much as I want to give you at this time. If you want more, be sure put a comment at the end of this question. If you do it within an hour, I'll just edit the question. Otherwise, I'll use comments.

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katrin2010 [14]

Answer:

1) A = (3 + 5·i) + (2 - 3·i)

2) A = (-3 + 5·i) + (-2 - 3·i)

3) A = (-3 + 5·i) + (2 + 3·i)

4) A = (3 - 5·i) + (2 + 3·i)

Step-by-step explanation:

1) For the first chart, we have;

To go from the start point to get the new line, we add the coordinates of the red line end point to the coordinates of the starting line end point as follows

A = (3 + 5·i) + (2 - 3·i)

2) For the second chart, we have;

To go from the start point to get the new line, we add the coordinates of the red line end point to the coordinates of the starting line end point as follows

A = (-3 + 5·i) + (-2 - 3·i)

3) For the third chart, we have;

To go from the start point to get the new line, we add the coordinates of the red line end point to the coordinates of the starting line end point as follows

A = (-3 + 5·i) + (2 + 3·i)

4) For the fourth chart, we have;

To go from the start point to get the new line, we add the coordinates of the red line end point to the coordinates of the starting line end point as follows

A = (3 - 5·i) + (2 + 3·i)