Turn it to improper fractions.
4 1/4 divided by 2/7
Divide them.
17/4 divided by 2/7
17 2 17 x 7
--- ÷ --- = --------- = 119/8 OR 14 7/8
4 7 4 x 2
-----------------------------------------------------
Distribute to take out the parentheses.
(x + 8) - (-3x - 5)
Combine like terms.
x + 8 + 3x + 5
Answer.
4x + 13
Answer:
Check below, please
Step-by-step explanation:
Step-by-step explanation:
1.For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.)
When the derivative of a function is equal to zero, then it occurs when we have either a local minimum or a local maximum point. So for our x-coordinates we can say

2. For which values of x is f '(x) positive?
Whenever we have

then function is increasing. Since if we could start tracing tangent lines over that graph, those tangent lines would point up.

3. For which values of x is f '(x) negative?
On the other hand, every time the function is decreasing its derivative would be negative. The opposite case of the previous explanation. So

4.What do these values mean?

5.(b) For which values of x is f ''(x) zero?
In its inflection points, i.e. when the concavity of the curve changes. Since the function was not provided. There's no way to be precise, but roughly
at x=-4 and x=4
m<P would be:
25
but m<PQC I forgot how to do... sorry!
Answer:
A.

Negative reciprocal gives you the perpendicular slope so negative reciprocal of 1/2 is -2.
Then apply point-slope form.
B. The answer is x = 6.
The midpoint of JK is

The line that goes through JK is just a horizontal line
because the y-coordinate does not change. So its perpendicular bisector is the vertical line that goes through the x-coordinate of the midpoint, that is,
.