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Alja [10]
3 years ago
6

) For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.) x = (No Response) For which values of x

is f '(x) positive? (Enter your answer using interval notation.) (No Response) For which values of x is f '(x) negative? (Enter your answer using interval notation.) (No Response) What do these values mean? f is (No Response) when f ' > 0 and f is (No Response) when f ' < 0. (b) For which values of x is f ''(x) zero? (Enter your answers as a comma-separated list.)
Mathematics
1 answer:
grigory [225]3 years ago
6 0

Answer:

Check below, please

Step-by-step explanation:

Step-by-step explanation:

1.For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.)

When the derivative of a function is equal to zero, then it occurs when we have either a local minimum or a local maximum point. So for our x-coordinates we can say

 f'(x)=0\: at \:x=2, and\: x=-2

2. For which values of x is f '(x) positive?

Whenever we have  

 f'(x)>0

then function is increasing. Since if we could start tracing tangent lines over that graph, those tangent lines would point up.

 f'(x)>0 \:at [-4,-2) \:and\:(2, \infty)

3. For which values of x is f '(x) negative?  

On the other hand, every time the function is decreasing its derivative would be negative. The opposite case of the previous explanation. So

 f'(x)

4.What do these values mean?

 f(x) \:is \:increasing\:when\:f'(x) >0\\\\f(x)\:is\:decreasing\:when f'(x)

5.(b) For which values of x is f ''(x) zero?

In its inflection points, i.e. when the concavity of the curve changes. Since the function was not provided. There's no way to be precise, but roughly

at x=-4 and x=4

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3 0
3 years ago
Given circle and circle with radii of 6cm and 4cm respectively.
noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

\angle EAF = \theta = 140^\circ

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

                                    = 14.653 cm

In circle C

\angle GCH = \theta = 140^\circ

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

                                   $=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

                                    = 9.769 cm    

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is  1.5 times the length of GH

i.e.                   14.653  = 1.5 x 9.769

                       14.653 = 14.653

Hence proved.

                             

6 0
3 years ago
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Answer:

Step-by-step explanation:

Let John's age be x. This gives us that in 11 years, john's age will be 5 less than 5 times his current age. Therefore, we could get: x+11=5x-5. This is your second equation. Solving for x, we get 4x=16 so x=4.

5 0
3 years ago
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The ticket at a concert are selling for $12.00. Juanita is going with a group of 25 people. There is a discount of 1/8 off each
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1/8 off each
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