Please help-Due tonight-12:00 pm I will mark brainlest if it is right

Leona purchased a $1,000 bond having a quoted price of 99.875. She had to pay a 5.5% brokerage fee (of the selling price). What

Ede4ka [16]

Answer:

None of these choices are correct.

Step-by-step explanation:

The quoted value of 99.875, means that this bond is sold at 99.875% of the face value and not at a price of $99.875.

Therefore, calculate price;

Price = 0.99875 * 1000

Price = $998.75

Since brokerage fees is 5.5% of the selling price, Leona will pay additional cost to the quoted price making the total cost to be more than $998.75;

Brokerage fees = (0.055*998.75) = $54.93

Total cost = $998.75 +$54.93

= $1053.68

Therefore, none of the choices is correct.

3 0

2 years ago

Which number-line model represents the sum of 3/4 + ( - 1.75) ?

Fed [463]

Answer:

A

Step-by-step explanation:

6 0

2 years ago

Which amount is greater, 5 feet or 2 yards?

Vedmedyk [2.9K]

Answer:

2 yards

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100

gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of 660, hence $\mu = 660$ .

The standard deviation is of 90, hence $\sigma = 90$ .

A sample of 100 is taken, hence $n = 100, s = \frac{90}{\sqrt{100}} = 9$ .

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$