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Evgesh-ka [11]
3 years ago
14

In fifteen minutes, greg's sailboat went 3/6 mile, gina's sailboat went 6/6 mile, and Stuart's sailboat went 4/6 mile. Whose sai

lboat went the longest distance in fifteen minutes?
Mathematics
2 answers:
sattari [20]3 years ago
7 0
Gina's boat 6/6 is the full mile in fifteen minutes
Radda [10]3 years ago
5 0
To make this situation easier to understand, you must simplify these fractions.  3/6 is equal to 0.5
6/6 is equal to 1
4/6 is equal to 0.3333 repeating.

With this info we can tell that Gina's sailboat went to longest distant in the fifteen minutes.

Hope this helps! :)
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The quadratic formula is:

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In this case, a = 2, b = -3, and c = -7

So, we can plug in the numbers to get:

  \frac{-(-3) + \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)} and    \frac{-(-3) - \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)}

Simplifying, we get:

    \frac{3 + \sqrt{65} }{4} and   \frac{3 - \sqrt{65} }{4}

You need to use a calculator to find what these would be in decimal form. The answer, rounded to the nearest tenth, is: x = 2.8, x = -1.3

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Answer:

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3 years ago
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Answer:

D) cot(C) = 1/2.

Step-by-step explanation:

We can go through each choice and examine is validity.

Choice A)

We have:

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Recall that secant is the ratio of the hypotenuse to the adjacent.

With respect to B, the adjacent is 6 and the hypotenuse is 7.

Therefore, sec(B) should be 7/6 instead.

A is incorrect.

Choice B)

We have:

\displaystyle \cot B=\frac{3}{2}

Cotangent is the ratio of the adjacent side to the opposite.

With respect to B, the adjacent side is 6 and the opposite side is 3.

Therefore, cot(B) = 6/3 = 2.

B is incorrect.

Choice C)

C is incorrect for the reasons listed in A.

Choice D)

We have:

\displaystyle \cot C=\frac{1}{2}

Again, cotangent is the ratio of the adjacent side to the opposite.

With respect to C, the adjacent side is 3 and the opposite side is 6.

So, cot(C) = 3/6 = 1/2.

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