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mafiozo [28]
3 years ago
9

G squared multiplied by G squared

Mathematics
1 answer:
Lapatulllka [165]3 years ago
7 0

Answer:

G to the power of 4

Step-by-step explanation:

You would add the powers but leave the base alone since it’s the same.

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To find the answer all you have to do is subtract 10 from 526.

So, 526 - 10 = 516

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+<br> (10x+2)<br> →<br> (9X+18) find the value of x
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16

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10x+2=9x+18

-2 -2

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Let (6,-5) be a point on the terminal side of θ. Find the exact values of sin θ, sec θ, and tan θ.
makvit [3.9K]

Answer:

sinθ = -5/√61

secθ = √61/6

tanθ = -5/6

Step-by-step explanation:

From the given coordinate (6, -5), x = 6 and y = -5. This shows that the point lies in the 4th quadrant. In the fourth quadrant, only cos θ is positive, both sin θ and tan θ are negative.

Let us get the value of the radius 'r' first before calculating the trigonometry identities.

Using the Pythagoras theorem;

r^2 = x^2 + y^2\\r^2 = 6^2 + (-5)^2\\r^2 = 36+25\\r^2 = 61\\r = \sqrt{61}

Using SOH, CAH, TOA to get the trigonometry identities;

Given x = 6, y =5 and r = √61

sin \theta = opp/hyp = y/r\\sin \theta = 5/\sqrt{61} \\

Since sin θ, is negative in the fourth quadrant, sin \theta = -5/\sqrt{61} \\

cos \theta = adj/hyp = x/r\\cos \theta = 6/\sqrt{61} \\

sec \theta = \frac{1}{cos \theta} \\sec \theta = \frac{1}{6/\sqrt{61}  } \\sec \theta = \frac{\sqrt{61} }{6}

For tanθ:

tan \theta = \frac{opp}{adj} = \frac{y}{x}  \\tan \theta = \frac{5}{6}\\

Since tan θ, is negative in the fourth quadrant, tan \theta = -5/6

7 0
3 years ago
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