A class has LESS THAN 30 students
we must find what number is less than 30 and divides into both 4 and 8 so that we don't have a fraction of a student owning a football boot
the class could have 8 students
the class could have 16 students
the class could have 24 students
<u>lets assume that the class has the max possible so </u>
<u>24 in the class</u>
so we must find a coommon denomenator (bottom number) to keep the fractions the same we must multiply it by 1 or (number)/(same number as on top) or 1/1
so 3/4 times 2/2=6/8
7/8
so we must assume that the ones who own footballs also have boots (and not some other random person) so
6/8 or 3/4 of the class owns both football boots so
3/4 times 24=18
18 students own football boots
Answer:
(-1,-8)
Step-by-step explanation:
Multiply each value of midpoint by 2 and take away given points coordinates
Answer: 13.722 km ; or, write as: 13 13/18 km .
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Explanation:
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Area = Length * width ;
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or, write as: A = L * w ;
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Given: A = 247 km² ;
L = 18 km ;
w = "y" ;
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Find: "y"
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A = L * w ;
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Plug in our values:
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247 km² = 18 km * "y" ; solve for "y" (in units of "km") ;
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18 y = 247 ;
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Divide each side of the equation by "18"; to isolate "y" on one side of the equation; and to solve for "y" :
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18 y / 18 = 247 / 18 ;
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to get:
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y = 13.7222222222222222...... km ; round to: 13.722 km
or; y = 13 13/18 km .
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Answer:
89
Step-by-step explanation:
Multiply first
12 times 7=84
Add 5 which makes 89
Hope this helped
:)
