Answer:
![\large\boxed{A=153\ cm^2}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BA%3D153%5C%20cm%5E2%7D)
Step-by-step explanation:
<em>Look at the picture.</em>
We have
square with side length a = 9
trapezoid with base lengths b₁ = 9 and b₂ = 6 and the height length h = 6
right triangle with legs lengths l₁ = 3 + 6 = 9 and l₂ = 6
The formula of an area of a square
![A=a^2](https://tex.z-dn.net/?f=A%3Da%5E2)
Substitute:
![A_I=9^2=81\ cm^2](https://tex.z-dn.net/?f=A_I%3D9%5E2%3D81%5C%20cm%5E2)
The formula of an area of a trapezoid:
![A=\dfrac{b_1+b_2}{2}\cdot h](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7Bb_1%2Bb_2%7D%7B2%7D%5Ccdot%20h)
Substitute:
![A_{II}=\dfrac{9+6}{2}\cdot6=\dfrac{15}{2\!\!\!\!\diagup_1}\cdot6\!\!\!\!\diagup^3=(15)(3)=45\ cm^2](https://tex.z-dn.net/?f=A_%7BII%7D%3D%5Cdfrac%7B9%2B6%7D%7B2%7D%5Ccdot6%3D%5Cdfrac%7B15%7D%7B2%5C%21%5C%21%5C%21%5C%21%5Cdiagup_1%7D%5Ccdot6%5C%21%5C%21%5C%21%5C%21%5Cdiagup%5E3%3D%2815%29%283%29%3D45%5C%20cm%5E2)
The formula of an area of a right triangle:
![A=\dfrac{l_1l_2}{2}](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7Bl_1l_2%7D%7B2%7D)
Substitute:
![A_{III}=\dfrac{(9)(6)}{2}=\dfrac{54}{2}=27\ cm^2](https://tex.z-dn.net/?f=A_%7BIII%7D%3D%5Cdfrac%7B%289%29%286%29%7D%7B2%7D%3D%5Cdfrac%7B54%7D%7B2%7D%3D27%5C%20cm%5E2)
The area of the shape:
![A=A_I+A_{II}+A_{III}\\\\A=81+45+27=153\ cm^2](https://tex.z-dn.net/?f=A%3DA_I%2BA_%7BII%7D%2BA_%7BIII%7D%5C%5C%5C%5CA%3D81%2B45%2B27%3D153%5C%20cm%5E2)
Answer:
Step-by-step explanation:
hello :
√(5/4)= √5/ √4 =√5/2 = (1/2)√5
3+√5/4−√5 = 3+(1/2)√5 so : a=3 and b= 1/2
6/35 is your answer answer answer sorry
Answer:
I'm pretty sure that your answere would be B.have a good day!
Answer:
$0.14 per ounce of salsa
Step-by-step explanation:
2.80/20
Move decimal to make the number a whole number
(Have to move the decimal the same amount of spaces)
28/200
0.14
Hope this helps. Have a nice day