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3 years ago

HELLLLLLLLLLLPPPP. I have a test on this on friday and I need to understand it!

Mathematics

1 answer:

kramer3 years ago

5 0

Answer:

The smallest number n could be is 64.

Step-by-step explanation:

35 + 64 = 99

64/8 = 8

$\sqrt{64+225}$ = √289 = 17

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A sociologist recorded the estimated life expectancies of women born in Center City. Use the data from women born in 1970 and 20

Veronika [31]

$Y=0.213x-352$ will represent this linear model shown in the data table.

<h3>What will be the linear model for the given data?</h3>

Put the values of the x in the all given equations and then check the value of y if the value of y matches the given values in the option

So if we put the value x=1980 in the $Y=0.213x-352$ then

$Y=0.213(1980)-352$

$Y=69.74$

These values are closest to 70.1 whereas other options do not satisfy the condition.

Thus $Y=0.213x-352$ will represent this linear model shown in the data table.

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3 0

2 years ago

Write an equation for this model and solve for `x`

WARRIOR [948]

The equation is -5x = 4

x = -0.8

4 0

2 years ago

Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

lys-0071 [83]

<em>Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work. </em>

<em>But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.</em>

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

$2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$

Lets divide the expression by $2x^2\:-\:3x\:+\:1$

Solution Steps:

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}$

Factorizing

$2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}$

Factorizing

$2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}$

$\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2$

$x^2+5x-2$

Thus,

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2$

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Keywords: expression, division

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3 0

3 years ago

Read 2 more answers

Which distance measures 7 units?

GrogVix [38]

Answer:

M to P

Step-by-step explanation:

It goes 7 hops from -1 to 6

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3 years ago

What is the Prime Factors of 10

Drupady [299]

Answer:

2, 5

Step-by-step explanation:

10 = 2 × 5 . . . . . . both of these factors are prime

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3 years ago