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Ksivusya [100]
2 years ago
8

Can someone please help me with a few of theseee

Mathematics
1 answer:
charle [14.2K]2 years ago
7 0

i dont know, sorry.

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Rewrite the expression g+1/6d-3/4g+1/9g-g+1/4d in standard from by combining like terms I need this ASAP AND I NEED ALL STEPS TO
GarryVolchara [31]

Answer:

(5/12)d - (23/36)g

Step-by-step explanation:

First you can eliminate g and -g to get (1/6)d - (3/4)g + (1/9)g + (1/4)d. Then you need to get common denominators to add like terms together.

1/6 = 4/24 and 1/4 = 6/24. Add them together to get (10/24)d or (5/12)d.

-3/4 = -27/36 and 1/9 = 4/36. Add them together to get (-23/36)g.

So in standard form, (5/12)d - (23/36)g

5 0
3 years ago
(15.2*0.25-48.51/14.7)/x=(13/44-2/11-5/66/2.50)1.2/(3.2+0.8(5.5-3.25)
goldfiish [28.3K]

Answer:

x = 41.67

Step-by-step explanation:

The above equation, would be simplified or divided into parts;

Therefore, the given equation becomes;

A/x = B/C

Where;

A = (15.2*0.25-48.51/14.7)

B = (13/44-2/11-5/66/2.50)1.2

C = 3.2+0.8(5.5-3.25)

x = unknown variable.

<u>Part A</u>

(15.2*0.25-48.51/14.7) = (15.2*0.25 - 3.3)

A = (3.8 - 3.3)

A = 0.5

<u>Part B</u>

(13/44-2/11-5/66/2.50)1.2 = (0.3 - 0.18 - 0.030) * 1.2

B = 0.09 * 1.2

B = 0.108

<u>Part C</u>

(3.2+0.8(5.5-3.25)

C = 4*(2.25)

C = 9

<em>Substituting the values into the equation, we have;</em>

0.5/x = 0.108/9

<em>Cross-multiplying, we have;</em>

9 * 0.5 = 0.108x

4.5 = 0.108x

x = 4.5/0.108

x = 41.67

6 0
2 years ago
Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other.
erastovalidia [21]

The Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other is given below.

<h3>What are the proves?</h3>

1.  To know  collinear vectors:

∧ ⁻a ║ ⁻a

If  ⁻b = ∧ ⁻a

then |⁻b| = |∧ ⁻a|

So one can say that  line ⁻b and ⁻a are  collinear.

2.  If ⁻a and ⁻b  are collinear

Assuming |b| length  is  'μ' times of |⁻a |

Then | 'μ' ⁻a| = | 'μ' ⁻a|

So  ⁻b = 'μ' ⁻a

Learn more about vectors  from

brainly.com/question/25705666

#SPJ1

3 0
2 years ago
Find the center and radius for the circles with the following equation x^2+y^2-4x+6y+11=0
Vera_Pavlovna [14]
Rearrange x²+y²-4x+6y=-11 I'll tell you an easy way. take the coefficient of x and divide it by -2 and the coefficient of y and divide it by -2  so -4 ÷-2 = 2           6÷-2= -3 (2,-3) is the center of the circle to know the radius √2² + -3² + -11  =√2  The Radius equals √2
7 0
3 years ago
If f(x)=3x^2+1 and g(x)=1-x, what is the value of (f-g)(2)?
madam [21]
The answer is 14 you just have to substitute x with the given number and finish the equation
3 0
3 years ago
Read 2 more answers
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