I am stumped on Question 2

Mathematics

2 answers:

Lyrx [107]3 years ago

8 0

Answer:

It would be easiest to convert them all to fractions out of 100. The bigger is is, the more likely it will happen - for example something with a 2/100 (2 out of 100 chance) of happening is less likely to happen than something with a 98/100 (98 out of 100 chance).

60% = 60/100

8 out of 10 = 8/10 = 80/100 (multiply 8/10 by ten)

0.37 = 37/100

20% = 20/100

5/6 = .83 = 83/100

When you put these in order from least to greatest you get:

20%

0.37

60%

8 out of 10

5/6

Tomtit [17]3 years ago

4 0

Answer:

Step-by-step explanation:

A.60/100=3/5

B.10-8=2

D.20/100=5

C.0.37=

E.5/6=0.83

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BARSIC [14]

Answer:

(c) Equation which can be used to find r, the cost in dollars to park s nights is r = 24.99 s

Step-by-step explanation:

Here, the parking cost of 1 night at the airport = $24.99

Now, here the total number of nights the car is parked at airport = s

R = The total cost of parking s nights

Now, The cost for parking s nights = s x ( Cost of parking 1 night)

= s x ($24.99) = 24.99 s

Also the cost for parking s nights = r

⇒ r = 24.99 s

Hence, equation which can be used to find r, the cost in dollars to park s nights is r = 24.99 s

4 0

3 years ago

(3squared)squared x(10cubed)squared

kiruha [24]

Hii :))

$\tt {(3 ^{2} )}^{2} \times {(10^{3}) }^{2} \\ \tt = (3 \times 3) ^{2} \times {(10 \times 10 \times 10)}^{2} \\ \tt \: = {9}^{2} \times 1000 ^{2} \\ \tt = (9 \times 9) \times (1000 \times 1000) \\ = \tt \: 81 \times 1000000 \\ = \boxed{\tt \: 81000000}$