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sergiy2304 [10]
3 years ago
9

The circumference of Z is 84 cm. What is the length of xy (the minor arc)?

Mathematics
1 answer:
Orlov [11]3 years ago
6 0

Answer:21 cm

Step-by-step explanation: The circle's circumference is 84 cm. 84 / 4 = 21. Therefore the length of the arc XY is 21 cm.

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Surface area of a rectangular prism with side lengths of 5, 9 and 2
KIM [24]

Answer:

Right rectangular prism

Step-by-step explanation:

5 0
2 years ago
State the domain and range of the following relation<br> x^2+y^2=16
Vlada [557]

The domain and range is  [-4, 4] and [0, 4]

<h3 /><h3>What is Domain and range?</h3>

The domain of a function is the set of values that we are allowed to plug into our function.

The range of a function is the set of values that the function assumes.

x² + y² = 16

y = √16 - x²

For domain under root should not be negative quantity,

16 - x²≥0

16≥x²

So, x≤4 or x≥4

Thus, the domain is  [-4, 4]

Range:

y is maximum at x=0, y=4

y is minimum at x=4, y=0

Thus, range = [0, 4]

Learn more about domain and range here:

brainly.com/question/12751831

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8 0
2 years ago
What is five billion two hundred fifty four million seventy one thousand nine hundred twenty six written in standard form
lakkis [162]

5,254,071,926

Is the standard form

4 0
3 years ago
Tan(x)=2
nydimaria [60]
<span>Tan(x)=2
Or for x=45 tan(x)=1
then for tan(x)=2 ; x must be superior to 45 
Then the answer is </span><span>d. 63.4 degrees</span> 
8 0
3 years ago
Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u &gt; 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
3 years ago
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